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NeTakaya
3 years ago
9

what is the difference in there elevation an airplane flies at an altitude of 25,000 feet a submarine dives to a depth of 600 fe

et below sea level
Mathematics
1 answer:
Andru [333]3 years ago
7 0

I did 25,000 - (-500) = 25,600

I did -500 (negative 500) because it is below the sea level and positive 25,000 because it above the sea level

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stiv31 [10]

Step-by-step explanation:

<em>2</em><em>x</em><em>(</em><em>x-5</em><em>)</em><em>+</em><em>3</em><em>(</em><em>x-2</em><em>)</em><em>=</em><em>8</em><em>+</em><em>7</em><em>(</em><em>x-4</em><em>)</em>

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2x²<em>-</em><em>x</em><em>=</em><em>1</em>

<em>2</em><em>x</em><em>=</em><em>1</em>

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<em>Hope</em><em> </em><em>you </em><em>get</em><em> </em><em>it</em><em> </em><em>please</em><em> </em><em>someone</em><em> </em><em>shou</em><em>ld</em><em> </em><em>verify</em><em>.</em><em>.</em><em>.</em><em>.</em>

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Using FOIL method. Multiply the terms. (X^2 -7)(x^2 -4)
murzikaleks [220]

Answer:

x^4-11x^2+28

Step-by-step explanation:

  1. Set it up

x^2(x^2-4) -7(x^2-4)

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3 years ago
7. Use the quadratic formula to find the solution(s). x² + 2x - 8 = 0​
morpeh [17]

Hey there!

<u>Use the quadratic formula to find the solution(s). x² + 2x - 8 = 0</u>

  • Answer :

x = -4 or x = 2 ✅

  • Explanation :

<em><u>Quadratic</u></em><em><u> </u></em><em><u>formula </u></em><em><u>:</u></em><em><u> </u></em>ax² + bx + c = 0 where a ≠ 0

The number of real-number solutions <em>(roots)</em> is determined by the discriminant (b² - 4ac) :

  • If b² - 4ac > 0 , There are 2 real-number solutions

  • If b² - 4ac = 0 , There is 1 real-number solution.

  • If b² - 4ac < 0 , There is no real-number solution.

The <em><u>roots</u></em> of the equation are determined by the following calculation:

x =  \frac{ - b \pm  \sqrt{ {b}^{2} - 4ac } }{2a}

Here, we have :

  • a = 1
  • b = 2
  • c = -8

1) <u>Calculate </u><u>the </u><u>discrim</u><u>i</u><u>n</u><u>ant</u><u> </u><u>:</u>

b² - 4ac ⇔ 2² - 4(1)(-8) ⇔ 4 - (-32) ⇔ 36

b² - 4ac = 36 > 0 ; The equation admits two real-number solutions

2) <u>Calculate </u><u>the </u><u>roots </u><u>of </u><u>the </u><u>equation</u><u>:</u>

▪️ (1)

x_1 =  \frac{ - b -  \sqrt{ {b}^{2}  - 4ac} }{2a}  \\  \\ x_1 =  \frac{ - 2 -  \sqrt{36} }{2(1) }  \\  \\ x_1 =  \frac{ - 2 - 6}{2}   \\ \\ x_1 =  \frac{ - 8}{2}  \\  \\ \blue{\boxed{\red{x_1 = -4}}}

▪️ (2)

x_2 =  \frac{ - b  +   \sqrt{ {b}^{2} - 4ac } }{2a}  \\  \\ x_2 =  \frac{ - 2 +  \sqrt{36} }{2(1)}  \\  \\ x_2 =  \frac{ - 2 + 6}{2}  \\  \\ x_2 =  \frac{4}{2}  \\  \\ \red{\boxed{\blue{x_2 = 2}}}

>> Therefore, your answers are x = -4 or x = 2.

Learn more about <u>quadratic equations</u>:

brainly.com/question/27638369

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2 years ago
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Answer:

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