What is the slope of the line?

H(-4), h(0), h(4), h(8)

DIA [1.3K]

9514 1404 393

Answer:

see attached

Step-by-step explanation:

The first two x-values, -4 and 0, fall in the first part of the function definition.

There is no function definition for x = 4, as the second part only applies for x > 4.

The last x-value, 8, falls in the second part of the function definition.

The function is evaluated by putting the x-value where x is in the expression and doing the arithmetic. For example, ...

h(-4) = -(-4+1)^2 +7 = -(-3)^2 +7 = -9 +7 = -2

h(0) = 6

h(4) = undefined

h(8) = -8/3

6 0

2 years ago

Which is the correct algebraic representation for the area of a circle?

fiasKO [112]

B because pie radius square = area of a circle

4 0

3 years ago

Help for question 1 and 2

AnnyKZ [126]

Answer:

(1). $5^{4}$ × $13^{7}$ ; (2). 3 - 5x

Step-by-step explanation:

1). [( - 5 )³ · ( - 5 )] ( $13^{-2}$ · $13^{9}$ ) = $(-5)^{3+1}$ × $(13)^{-2+9}$ = $(-5)^{4}$ × $13^{7}$ = $5^{4}$ × $13^{7}$

2). - 25x² ÷ 5x + 15x ÷ 5x = 3 - 5x

4 0

1 year ago

50 pts please help me due today links or incorrect answers will get reported

Bumek [7]

Using the normal distribution, the area underneath the shaded region between the two z-scores is given by:

C. 0.6766.

<h3>Normal Probability Distribution</h3>

The z-score of a measure X of a normally distributed variable with mean $\mu$ and standard deviation $\sigma$ is given by:

$Z = \frac{X - \mu}{\sigma}$

The z-score measures how many standard deviations the measure is above or below the mean.

Looking at the z-score table, the p-value associated with this z-score is found, which is the percentile of X.

Hence, for this problem, the area is the p-value of z = 0.75 subtracted by the p-value of z = -1.3.

Looking at the z-table, the p-values are given as follows:

z = 0.75: 0.7734.

z = -1.3: 0.0968.

Then:

0.7734 - 0.0968 = 0.6766.

Which means that option C is correct.

More can be learned about the normal distribution at brainly.com/question/15181104

#SPJ1

3 0

1 year ago

The base of a solid is the region enclosed by the graphs of y=e^x, y=0, x=0, and x = 1. If each cross-section perpendicular to t

yanalaym [24]

Answer:

A

Step-by-step explanation:

The base of a solid in the region enclosed by the graphs of y = eˣ, y = 0, x = 0, and x = 1. Each cross-section perpendicular to the x-axis is an equilateral triangle. We want to find the volume of the solid.

Please refer to the graph below. We are concerned with the red region.

In order to find the volume, we essentially sum up the area of the figure at each x value. So, we integrate from x = 0 to x = 1.

The area for an equilateral triangle is given by:

$\displaystyle A=\frac{\sqrt{3}}{4}s^2$

Where s is the side length of the triangle.

Since the triangle lies perpendicular on the region, the side length of the triangle at x is simply y, which is eˣ.

Therefore, our volume is:

$\displaystyle V=\int_0^1\frac{\sqrt3}{4}(y)^2\, dx$

Substitute:

$\displaystyle V=\int_0^1\frac{\sqrt3}{4}(e^x)^2\, dx$

Evaluate the integral. Simplify:

$\displaystyle V=\frac{\sqrt3}{4}\int_0^1e^{2x}\, dx$

Integrate using u-substitution:

$\displaystyle V=\frac{\sqrt3}{8}\left(e^{2x}\Big|_0^1\right)$

Evaluate:

$\displaystyle V=\frac{\sqrt3}{8}\left(e^{2(1)}-e^{2(0)} \right)$

Therefore, the volume of the solid is:

$\displaystyle V=\frac{\sqrt3}{8}\left(e^2-1\right)$

Our answer is A.

3 0

2 years ago

Read 2 more answers