Answer:
zero
Step-by-step explanation:
The question is incomplete, here is the complete question:
Recall that m(t) = m.(1/2)^t/h for radioactive decay, where h is the half-life. Suppose that a 500 g sample of phosphorus-32 decays to 356 g over 7 days. Calculate the half life of the sample.
<u>Answer:</u> The half life of the sample of phosphorus-32 is 
<u>Step-by-step explanation:</u>
The equation used to calculate the half life of the sample is given as:

where,
m(t) = amount of sample after time 't' = 356 g
= initial amount of the sample = 500 g
t = time period = 7 days
h = half life of the sample = ?
Putting values in above equation, we get:

Hence, the half life of the sample of phosphorus-32 is 
Answer:
LCD = 30
3/10 = 9/30
2/3 = 20/30
Step-by-step explanation:
This is the answer because:
1) First, the least common denominator is 30 because 10 x 3 is 30 and 3 x 10 is 30
2) Next, multiply the numerators with the same number you multiplied with the denominator
3 x 3 = 9
2 x 10 = 20
3) Therefore, the answers are:
3/10 = 9/30
2/3 = 20/30
Hope this helps!
Answer:
a. 1.2
Step-by-step explanation:
b. 0.4
Because the probability of getting heads is 1/2, in a scenario in which it is tossed 3 times, the probability of getting exactly one head is 1/3.