<h3>
Answer: Yes they are equivalent</h3>
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Work Shown:
Expand out the first expression to get
(a-3)(2a^2 + 3a + 3)
a(2a^2 + 3a + 3) - 3(2a^2 + 3a + 3)
2a^3 + 3a^2 + 3a - 6a^2 - 9a - 9
2a^3 + (3a^2-6a^2) + (3a-9a) - 9
2a^3 - 3a^2 - 6a - 9
Divide every term by 2 so we can pull out a 2 through the distributive property
2a^3 - 3a^2 - 6a - 9 = 2(a^3 - 1.5a^2 - 3a - 4.5)
This shows that (a-3)(2a^2 + 3a + 3) is equivalent to 2(a^3 - 1.5a^2 - 3a - 4.5)
Answer:
not for sure sorry
Step-by-step explanation:
sorry
Remark
I don't know exactly what level you are in, but the obvious factors are
y = 2x*(x^3 + 11x + 30)
This gives one more factor somewhere around x = -11.3 . Notice that the minimum is around - 3000 or so. I don't think anyone is going to try and take this any further. My calculator figures out cubics and gives an answer of -11.23. There are two other roots but they are a complex pair.
Answer
factor 1: 2x
factor 2: x^3 + 11x^2 + 30
your answer will be f(x)=113−kx,f(−3)=121
