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DedPeter [7]
3 years ago
8

Can someone pleasetell mestep by step how to divide this?

Mathematics
1 answer:
sergejj [24]3 years ago
7 0
Multiply the 15 vans by 9. Then when you get your answer, divde that by 140.
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in cathys garden 5/6 of the area is planted with flowers. of the flowers 3/10 of them are red. what fraction of cathys garden is
Tamiku [17]
3/10 of 5/6....." of " means multiply
3/10 * 5/6 = 15/60 reduces to 1/4......1/4 of her garden has red flowers
4 0
3 years ago
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^^^ help would be appreciated
vova2212 [387]

Answer:

i think the answer is: 6:8

Step-by-step explanation:

you just add 5:6 + 1:2= 6:8 and to check, you subtract 6:8-1:2

6 0
3 years ago
Please help! no clue about these! asap and i will reward points!
lara31 [8.8K]
The hinge theorem. Just think of the two sides being connecting by a "hinge"
4 0
3 years ago
Plssss help
Andre45 [30]

Answer:

  • A) \displaystyle \frac{1}{77}.
  • B) \displaystyle \frac{12}{77}.
  • C) \displaystyle \frac{4}{11}.

Step-by-step explanation:

All marbles here are identical. Also, the question isn't concerned about the order in which the marbles are drawn. Thus, all calculations here shall be combinations rather than permutations.

<h3>A)</h3>

How many ways to choose three out of six identical red marbles without replacement?

\displaystyle _6C_3 = c(6, 3) = {6\choose 3} = 20.

Note that these three expressions are equivalent. They all represent the number of ways to choose 3 out of 6 identical items without replacement.

How many ways to choose three out of all the 6 + 10 + 6 = 22 marbles?

\displaystyle _{22} C_{3} = 1540.

The probability of choosing three red marbles out of these 22 marbles will be:

\displaystyle \frac{\text{Number of ways for choosing three out of six red marbles}}{\text{Number of ways to choose three out of 22 marbles}} = \frac{20}{1540} = \frac{1}{77}.

<h3>B)</h3>

How many ways to choose two out of six identical red marbles without replacement?

\displaystyle _6 C_2 = 15.

How many ways to choose one out of 10 + 6 = 16 non-red marbles?

_{16} C_1=16.

Choosing two red marbles does not influence the number of ways of choosing a non-red marble. Both event happen and are independent of each other. Apply the product rule to find the number of ways of choosing two red marbles and one non-red marble out of the pile of 22.

_6 C_2 \cdot _{16} C_1= 240.

Probability:

\displaystyle \frac{240}{1540} = \frac{12}{77}.

Double check that the order doesn't matter here.

<h3>C)</h3>

None of the marbles are red. In other words, all three marbles are chosen out of a pile of 10 + 6 = 16 white and blue marbles. Number of ways to do so:

_{16} C_{3} = 560.

Probability:

\displaystyle \frac{560}{1540}= \frac{4}{11}.

5 0
4 years ago
Read 2 more answers
Plz someone hurry....................
lana66690 [7]
Your Answer Is A , the guy on top is right
8 0
3 years ago
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