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Vinil7 [7]
2 years ago
8

Write a rule for g (pls help asap 50 pts )

Mathematics
2 answers:
BARSIC [14]2 years ago
8 0

Answer:

I can see that the point appears to shift up by 2 units. What else do I need to know in order to find a possible formula for g(x) in terms of f(x)?

As here it is either stretched or shrunk, we have  

i.e. while f(3)=2 , g(3)=2f(3)=2×2=4

Step-by-step explanation:

The graph of f'x) is the graph of g(x) after it has been vertically streched lies on the graph of f(x) g(x)=2f(x). The corresponding point on the graph g(x) formula for g(x) in trems of f(x) ?

If f(x) is vertically stretched or shrunk in a graph, we have multiplied by a number n , which is greater than 1 if it has stretched and if it is less than 1 (but grater than 0 ), it will shrink.

On the contrary just adding a will either shift it up - if it is positive - or shift it down - if it is negative.

As here it is either stretched or shrunk, we have  

i.e. while f(3)=2 , g(3)=2f(3)=2×2=4

Mazyrski [523]2 years ago
7 0

Answer:

g(x) = x is the base function.

To shrink it vertically by 1/2, make 1/3 the coefficient of the variable x.

To shift it 4 units to the right, subtract 4 from within the squared variable.

To shift 5 units down, subtract 5 from the entire function.

Step-by-step explanation:

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Step-by-step explanation: Expressions do not have equal signs (=), D is the correct answer.

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Answer:

Ok:

Step-by-step explanation:

I see that you set up 90 miles = 60 mph * t, where you found out that t = 1.5. What what you needed to do was set 180 miles = 45 mph * t. This is because it is 45 mph for the <em>whole</em> trip. Then, you find that t = 4 hours. That that means that he spent 2.5 hours driving back. Then, we can do d=vt and find 90/2.5 as the speed he went home at. Which comes out to be 36 mph.

8 0
3 years ago
Evelyn is making a candy that contains 25% dark chocolate and the rest milk chocolate. The candy has 3 pounds of milk chocolate.
Vitek1552 [10]

<em>Part A: </em>

Let c represent the total amount of chocolate there is in lbs.

c = 0.25c + 0.75c

<em>Part B: </em>

0.75c represents milk chocolate, and we know that there are 3 lbs of milk chocolate, so you can replace the 0.75c with 3 (representing 3 lbs):

c = 0.25c + 3

Divide all the terms by c:

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Subtract 0.25 from both sides to combine the like terms:

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Multiply all the terms by c to make the equation easier to work with:

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Divide both sides by 0.75 to isolate the c and find the total amount of chocolate in pounds.

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Substitute c for 4 in the term that defines dark chocolate (which was 0.25c)

0.25(4) = 1 pound

Therefore, there was exactly 1 pound of dark chocolate present in the chocolate.

This makes sense, as 1 pound of dark chocolate + 3 pounds of milk chocolate = 4 pounds of chocolate in total, and 1 is 25% of 4 and 3 is 75% of 4.


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3 years ago
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