Answer:
1. Allele frequency of b = 0.09 (or 9%)
2. Allele frequency of B = 0.91 (0.91%)
3. Genotype frequency of BB = 0.8281 (or 82.81%)
4. Genotype frequency of Bb = 0.1638 (or 16.38%)
Explanation:
Given that:
p = the frequency of the dominant allele (represented here by B) = 0.91
q = the frequency of the recessive allele (represented here by b) = 0.09
For a population in genetic equilibrium:
p + q = 1.0 (The sum of the frequencies of both alleles is 100%.)
(p + q)^2 = 1
Therefore:
p^2 + 2pq + q^2 = 1
in which:
p^2 = frequency of BB (homozygous dominant)
2pq = frequency of Bb (heterozygous)
q^2 = frequency of bb (homozygous recessive)
p^2 = 0.91^2 = 0.8281
2pq = 2(0.91)(0.9) = 0.1638
Answer:
Option-C
Explanation:
The sugar alcohols are the carbohydrates which are neither considered sugars nor alcohols but they partially resemble the structure of both of these sugars and alcohol.
The sugar alcohols are naturally present in the vegetables and fruits but they are also artificially synthesised like xylitol, lactitol, mannitol and others.
They are considered the alternative from of sugar but they provide less energy as compared to carbohydrates like they provide about 0-3 kcal per gram whereas sugar provides 4 kcal per gram.
This difference is due to the reason that they are not completely absorbed by the human body and also they are incompletely metabolized therefore provide less energy.
Thus, Option-C is the correct answer.
Answer:
Explanation:
porque una persona con dos alelos normales presentará un fenotipo normal, mientras que si las dos copias del gen son el alelo mutado que producen una enfermedad, el fenotipo expresará los síntomas característicos de esa enfermedad.
You are exercising, doing aerobics or a stair climber at your fitness center. as you increase to a high intensity of exercise, you would expect the tidal volume to increase and the frequency of respiration to increase.
