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exis [7]
3 years ago
14

A company has decided to use 0−1 integer programming to help make some investment decisions. There are three possible investment

alternatives from which to choose, but if it is decided that a particular alternative is to be selected, the entire cost of that alternative will be incurred (i.e., it is impossible to build one-half of a factory). The 0-1 integer programming model is as follows:MAX Z = 5000 X1 + 7000 X2 + 9000 X3s.t. 25000 X1 + 32000 X2 + 29000 X3 ≤ 62000 ........... (1)X1 + X2 + X3 ≤ 2 .............................................. (2)-X1 + X2 ≤ 0 ..................................................... (3)16 X1 + 14 X2 + 19 X3 ≤ 36 .............................. (4)All X1, X2, X3 must be either 0 or 1where X1 = 1 if alternative 1 is selected, 0 otherwiseX2 = 1 if alternative 2 is selected, 0 otherwiseX3 = 1 if alternative 3 is selected, 0 otherwiseSuppose you wish to add a constraint that stipulates that both alternative 1 and alternative 3 must be selected. How would this constraint be written?The correct answer is: X1 + X3 = 2, so I want to know how

Mathematics
1 answer:
artcher [175]3 years ago
3 0

Answer:

See explaination for the details

Step-by-step explanation:

See attachment please

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Hurry Please). The function f (x) models the value of goods that are imported into the United states, where x is the number of y
nata0808 [166]

Answer:

Answer 1: 15

Answer 2: 11.55

Answer 3: 1985

Step-by-step explanation:

your welcome (*_*)

8 0
3 years ago
Reduce to the lowest terms by canceling -14/9 times -3/7
maksim [4K]

Answer:

2/3

Explanation:

Given the below;

\frac{-14}{9}\times\frac{(-3)}{7}

We can see from the above that 9 is divisible by 3 and that 14 is divisible by 7, let's go ahead and reduce to the lowest term as shown below;

\frac{-14}{9}\times\frac{(-3)}{7}=\frac{-2}{3}\times\frac{(-1)}{1}=\frac{2}{3}

5 0
1 year ago
3 1/7 x 2 2/8 (multiply fractions)
k0ka [10]

Answer:

.214 if it is to 3 decimal places.

5 0
2 years ago
Solve the quadratic equation below for the exact values of x:<br> 4x^2-5=75
grandymaker [24]

Step-by-step explanation:

4 {x}^{2}  - 5 = 75 \\ 4 {x}^{2}  = 75 + 5 \\ 4 {x}^{2}  = 80 \\  {x}^{2}  =  \frac{80}{4}  \\  {x}^{2}  = 20 \\ x = \pm \sqrt{20}  \\ x = \pm 2 \sqrt{5}

6 0
3 years ago
The speeds of vehicles traveling on a highway are normally distributed with an unkown population mean and standard deviation. A
Maksim231197 [3]

Answer:

The 90% confidence interval would be given by (60.09;69.91)    

We are 90% confident that the true mean for the speeds of vehicles traveling on a highway is between 60.09 and 69.91 miles per hour.

Step-by-step explanation:

1) Previous concepts

A confidence interval is "a range of values that’s likely to include a population value with a certain degree of confidence. It is often expressed a % whereby a population means lies between an upper and lower interval".

The margin of error is the range of values below and above the sample statistic in a confidence interval.

Normal distribution, is a "probability distribution that is symmetric about the mean, showing that data near the mean are more frequent in occurrence than data far from the mean".

\bar X =65 represent the sample mean for the sample  

\mu population mean (variable of interest)

s=9 represent the sample standard deviation

n=11 represent the sample size  

2) Confidence interval

The confidence interval for the mean is given by the following formula:

\bar X \pm t_{\alpha/2}\frac{s}{\sqrt{n}}   (1)

In order to calculate the critical value t_{\alpha/2} we need to find first the degrees of freedom, given by:

df=n-1=11-1=10

Since the Confidence is 0.90 or 90%, the value of \alpha=0.1 and \alpha/2 =0.05, and we can use excel, a calculator or a table to find the critical value. The excel command would be: "=-T.INV(0.05,10)".And we see that t_{\alpha/2}=1.81

Now we have everything in order to replace into formula (1):

65-1.81\frac{9}{\sqrt{11}}=60.09    

65+1.81\frac{9}{\sqrt{11}}=69.91

So on this case the 90% confidence interval would be given by (60.09;69.91)    

We are 90% confident that the true mean for the speeds of vehicles traveling on a highway is between 60.09 and 69.91 miles per hour.

3 0
2 years ago
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