Question

If f(x)=3x^2+1 and g(x)=1-x, what is the value of (f-g)(2)?

Answer 1

Answer:

$(f-g)(2)=28$

Step-by-step explanation:

Given:

$f(x)=3x^2+1$

$g(x)= 1-x$

To find the equivalent expression of  $(f-g)(2)$.

$(f-g)(2) = f(2) - g(2)$

Find g(x)

$g(x)=1-x$

Sub x for 2

$g(2)=1-2$

$g(2)=-1$

Find f(x)

$f(x)=3x^2+1$

Sub x for 2

$f(2)=3(2)^2+1$

$f(2)=12+1$

$f(2)=12+1$

$f(2)=13$

Solve for the giving value

$(f-g)(2)$

$(13- (-1)) (2)$

$14(2)$

28

Answer 2

The answer should be 14.

You just have to substitute x with the given number and finish the equation.