Is there a diagram to this problem?
The volume of the other side would be 390mm 3 as well
Answer:
a) 0.8132 or 81.32%
b) 0.1868 or 18.68%
c) 0.6116 or 61.16%
d) 0.7667 minutes
e) 0.8667 minutes
f) 0.1 minutes
Step-by-step explanation:
a)
If f(x) = 0.85-0.35x (0<x<2) is the <em>PDF</em> and X is the random variable that measures the time it takes for a trainee to complete the task, the probability a trainee will complete the task in less than 1.31 minutes is P(X<1.31)
b)
The probability that a trainee will complete the task in more than 1.31 minutes is
P(X>1.31) = 1 - P(X<1.31) = 1 - 0.8132 = 0.1868
c)
The probability it will take a trainee between 0.25 minutes and 1.31 minutes to complete the task is P(0.25<X<1.31)
d)
the expected time it will take a trainee to complete the task
is<em> E(X)
</em>
e)
f)
Answer:
This approach often yields much more accurate results than the trapezoidal rule does. Again we divide the area under the curve into n equal parts, but for this rule n must be an even number because we're estimating the areas of regions of width 2Δx.