Step-by-step explanation:
Draw diagonal AC
The triangle ABC has sides 17 and 25
Say AB is 17, BC is 25
Draw altitude on side BC from A , say h
h = 17 sin B
Area = 25*17 sin B = 408
sin B = 24/25
In ∆ ABC
Cos B = +- 7/25
= 625 + 289 — b^2 / 2*25*17
b^2 = 914 — 14*17 = 676
b = 26
h = 17*24/25 = 408/25 = 16.32
Draw the second diagonal BD
In ∆ BCD, draw altitude from D, say DE =h
BD^2 = h^2 + {(25 + sqrt (289 -h^2) }^2
BD^2 = 16.32^2 + (25 + 4.76)^2
= 885.6576 + 266.3424
BD = √ 1152 = 33.94 m
Answer:
The answer is 68°
Step-by-step explanation:
<h3>
<u>Given</u>;</h3>
- A right angled-triangle IGH.
- where, m∠G = 90°
<h3><u>To </u><u>Find</u>;</h3>
We know that
tan θ = Opp ÷ Adj
tan θ = 5 ÷ 2
tan θ = 2.5
tan θ = 68.2 ≈ 68
We know that tan 68 = 2.5
Thus, The m∠I is 68°
<u>-TheUnknownScientist 72</u>
An area That rises above surrounding landforms and has a rounded top; lower and usually less steep than a mountain. ... A high, flat-topped landform with cliff-like sides; larger than a butte.
Hope this helps!
A i guess i just need points
Answer:
-24 degrees Celsius
Step-by-step explanation:
6 x -4 = -24
