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9966 [12]
3 years ago
15

Explain hovevou could estimate 22% of 78 to check if your answer is reasonable.

Mathematics
1 answer:
fomenos3 years ago
8 0

Answer:

78 rounds to 80, so find 10% of 80 and double it. 10% of 80 is 8. So, 20% of 80 is 16. Then, 22% of 78 is a little more than 16.

78 rounds to 80, and 22% is a little less than 25%. 25% (or one-fourth) of 80 is 20. So, 22% of 78 is a little less than 20.

Step-by-step explanation:

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Mr. K has 112 feet of fencing to enclose a new garden. What is the maximum area of the garden that he can enclose?
musickatia [10]

Answer:

759 square foot garden

Step-by-step explanation:

L= length

W= Width

Perimeter = 2(L + W)

112 = 2(L + W)

divide both sides by 2 and you get

56 = L + W

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6 0
3 years ago
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Over the interval 2 to 4 by how much does the function increse
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The answer is 2 because two plus two equals 4 and 4-2=2 so the answer is 2. Hope this could help a lot and this was a useful answer


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3 years ago
If there are 25 animals in total, how many dogs are at the kennel?
8_murik_8 [283]

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Step-by-step explanation:

7 0
3 years ago
⦁ In a simple random sample of 1219 US adults, 354 said that their favorite sport to watch is football. Construct a 95% confiden
fomenos

Answer:

95% confidence interval for the proportion of adults in the United States whose favorite sport to watch is football is [0.265 , 0.316].

Step-by-step explanation:

We are given that in a simple random sample of 1219 US adults, 354 said that their favorite sport to watch is football.

Firstly, the pivotal quantity for 95% confidence interval for the proportion of adults in the United States whose favorite sport to watch is football is given by;

        P.Q. = \frac{\hat p-p}{\sqrt{\frac{\hat p(1-\hat p)}{n} } } ~ N(0,1)

where, \hat p = proportion of adults in the United States whose favorite sport to watch is football in a sample of 1219 adults = \frac{354}{1219}

           n = sample of US adults  = 1291

           p = population proportion of adults

<em>Here for constructing 95% confidence interval we have used One-sample z proportion statistics.</em>

So, 95% confidence interval for the population proportion, p is ;

P(-1.96 < N(0,1) < 1.96) = 0.95  {As the critical value of z at 2.5%

                                                    significance level are -1.96 & 1.96}

P(-1.96 < \frac{\hat p-p}{\sqrt{\frac{\hat p(1-\hat p)}{n} } } < 1.96) = 0.95

P( -1.96 \times {\sqrt{\frac{\hat p(1-\hat p)}{n} } < {\hat p-p} < 1.96 \times {\sqrt{\frac{\hat p(1-\hat p)}{n} } ) = 0.95

P( \hat p-1.96 \times {\sqrt{\frac{\hat p(1-\hat p)}{n} } < p < \hat p+1.96 \times {\sqrt{\frac{\hat p(1-\hat p)}{n} } ) = 0.95

<u>95% confidence interval for p</u> = [ \hat p-1.96 \times {\sqrt{\frac{\hat p(1-\hat p)}{n} } , \hat p+1.96 \times {\sqrt{\frac{\hat p(1-\hat p)}{n} } ]

                         = [ \frac{354}{1219}-1.96 \times {\sqrt{\frac{\frac{354}{1219}(1-\frac{354}{1219})}{1219} } , \frac{354}{1219}+1.96 \times {\sqrt{\frac{\frac{354}{1219}(1-\frac{354}{1219})}{1219} } ]

                         = [0.265 , 0.316]

Therefore, 95% confidence interval for the proportion of adults in the United States whose favorite sport to watch is football is [0.265 , 0.316].

5 0
3 years ago
5x+y=0 use the intercepts to graph the equation
IRINA_888 [86]
Y-intercept:  Let x = 0.  Result: 5x=0, and x= 0.  y-intercept is (0,0).
Similarly, x-int. is (0,0) (after going thru the same procedure:  set y=0 and find x)

6 0
3 years ago
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