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Serga [27]
3 years ago
7

you have 33 marbles. Besides 1 group of 33 marbles, is it possible to divide the marbles into groups with the same number of mar

bles with no marbles left over
Mathematics
2 answers:
s344n2d4d5 [400]3 years ago
8 0
Yes hi could have 11 groups with 3
olasank [31]3 years ago
4 0
Yes you could have three groups of 11 with no marbles left over.
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givi [52]

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Step-by-step explanation:


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3 years ago
Solve the quadratic.<br><br><br> 4x^2+4-20=0<br><br><br><br><br> brainlist if you explain
frez [133]

Answer:

  • x = -1/2(1 +√21) ≈ -2.79129
  • x = -1/2(1 -√21) ≈ 1.79129

Step-by-step explanation:

We assume the middle term is supposed to be 4x.

We can remove a common factor of 4 to simplify this a bit.

  x^2 +x -5 = 0

This is of the form

  ax^2 +bx +c = 0

where a=1, b=1, c=-5.

__

The <em>quadratic formula</em> gives the solutions as ...

  x=\dfrac{-b\pm\sqrt{b^2-4ac}}{2a}

Filling in the given coefficients, we have ...

  x = (-1 ±√(1^2 -4·1·(-5)))/(2·1)

  x = (-1±√21)/2

The solutions are x = -1/2(1 +√21) and -1/2(1 -√21).

_____

<em>If what you wrote is what you intend</em>, then the equation simplifies to 4x^2 -16 = 0.

Dividing by 4 and factoring the difference of squares gives ...

  x^2 -4 = 0

  (x -2)(x +2) = 0

These factors are zero (hence their product is 0) for the values x = 2 and x = -2.

The solutions are x=2 and x=-2.

5 0
3 years ago
On December 13, 2007, one British pound was worth 2.04 U.S. dollars.
Alika [10]

Answer:

a) 5 pounds

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2 years ago
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