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3 years ago

7

you have 33 marbles. Besides 1 group of 33 marbles, is it possible to divide the marbles into groups with the same number of mar

bles with no marbles left over

2 answers:

s344n2d4d5 [400]3 years ago

8 0

Yes hi could have 11 groups with 3

olasank [31]3 years ago

4 0

Yes you could have three groups of 11 with no marbles left over.

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<img src="https://tex.z-dn.net/?f=%20%5Csqrt%7B2x%7D%20%2B%2012%20%3D%20x%20%2B%208%20" id="TexFormula1" title=" \sqrt{2x} + 12

Helga [31]

First note that $x\ge0$ ; otherwise $\sqrt{2x}$ is undefined as long as we're only looking for real solutions.

We can write

$\sqrt{2x}+12=x+8$
$\sqrt{2x}=x-4$
$2x=(x-4)^2$
$2x=x^2-8x+16$
$x^2-10x+16=0$
$(x-8)(x-2)=0$

$\implies x=8,x=2$

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3 years ago

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Answer:31 dived by 81 is 0.3703

Step-by-step explanation:

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3 0

3 years ago

Read 2 more answers

Nia has number cards for 2 3 8 9 and 5 what are the different ways Nia can arrange the cards to show only even numbers with the

PIT_PIT [208]

Answer:

23958, 23598, 25938, 25398, 29358, 29538....

Step-by-step explanation:

We have given the number cards for for 2 3 8 9 and 5. We have to find the different ways Nia can arrange the cards to show only even numbers with the 2 in the ten thousands place.

The number should be even numbers with two in the ten-thousand places.

Only 8 is left as an even number. So 8 would be at the one's place.

In the ten-thousand places, arrange the three digits 3,9 and 5 in the middle.

So there are 3*2=6 ways to arrange the middle three digits in the ten-thousand places.

23958, 23598, 25938, 25398, 29358, 29538....

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3 years ago