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2 years ago

15

Help please asap tysm! 10 brainly points! Will mark brainliest if you put in a random answer you will be reported! Tysm! <3 N

eed this asap please tysm!

2 answers:

Ludmilka [50]2 years ago

4 0

Answer:

The length of side EF is 10 units.

If there is any specific measurement for each unit, multiply 10 by the measurement amount.

Zanzabum2 years ago

4 0

Answer:

<u>10 units</u>

Step-by-step explanation:

The side of EF is 10 units

The side of DE is 10 units

The side of DF is about 14.1 units

You might be interested in

Which is bigger 2/3 1/8 or 3/4

sergeinik [125]

Answer:

3/4

Step-by-step explanation:

2/3= 0.6

1/8= 0.125

3/4= 0.75

<u>I convert the fractions into </u><u>decimals the decimal with the highest number in the tenths place is the biggest </u>

<u>Hope This Helps!</u>

6 0

3 years ago

Read 2 more answers

marysya [2.9K]

First, subtract to get the difference.
2.85 – 2.78 = 0.07

Next, divide 2.78 by 100
2.78 ÷ 100 = 0.0278
So, 0.0278 is 1%. Divide 0.07 by 0.0278 to get the answer.
0.07 ÷ 0.0278 ≈ 2.518
2.518 ≈2.5
Therefore, the percentage increase is approximately 2.5% (that's the answer).

Hope this helps!

8 0

2 years ago

Here is the image I need help with

Mama L [17]

Answer:

All I know for a fact is that number 10 is C

Step-by-step explanation:

4 0

2 years ago

The corners of a meadow are shown on a coordinate grid. Ethan wants to fence the meadow. What length of fencing is required?

Nuetrik [128]

Answer:

34.6 units

Step-by-step explanation:

The lenght of fencing required is the total distance between point A to B, B to C, C to D, and D to A. That is the distance between all 4 corners of the meadow.

The coordinates of the corners of the meadow is shown on a coordinate plane in the attachment. (See attachment below).

Let's use the distance formula to calculate the distance between the 4 corners of the meadow using their coordinates as follows:

Distance between point A(-6, 2) and point B(2, 6):

$AB = \sqrt{(x_2 - x_1)^2 + (y_2 - y_1)^2}$

Let,

$A(-6, 2)) = (x_1, y_1)$

$B(2, 6) = (x_2, y_2)$

$AB = \sqrt{(2 - (-6))^2 + (6 - 2)^2}$

$AB = \sqrt{(8)^2 + (4)^2}$

$AB = \sqrt{64 + 16} = \sqrt{80}$

$AB = 8.9$ (nearest tenth)

Distance between B(2, 6) and C(7, 1):

$BC = \sqrt{(x_2 - x_1)^2 + (y_2 - y_1)^2}$

Let,

$B(2, 6) = (x_1, y_1)$

$C(7, 1) = (x_2, y_2)$

$BC = \sqrt{(7 - 2)^2 + (1 - 6)^2}$

$BC = \sqrt{(5)^2 + (-5)^2}$

$BC = \sqrt{25 + 25} = \sqrt{50}$

$BC = 7.1$ (nearest tenth)

Distance between C(7, 1) and D(3, -5):

$CD = \sqrt{(x_2 - x_1)^2 + (y_2 - y_1)^2}$

Let,

$C(7, 1) = (x_1, y_1)$

$D(3, -5) = (x_2, y_2)$

$CD = \sqrt{(3 - 7)^2 + (-5 - 1)^2}$

$CD = \sqrt{(-4)^2 + (-6)^2}$

$CD = \sqrt{16 + 36} = \sqrt{52}$

$CD = 7.2$ (nearest tenth)

Distance between D(3, -5) and A(-6, 2):

$DA = \sqrt{(x_2 - x_1)^2 + (y_2 - y_1)^2}$

Let,

$D(3, -5) = (x_1, y_1)$

$A(-6, 2) = (x_2, y_2)$

$DA = \sqrt{(-6 - 3)^2 + (2 - (-5))^2}$

$DA = \sqrt{(-9)^2 + (7)^2}$

$DA = \sqrt{81 + 49} = \sqrt{130}$

$DA = 11.4$ (nearest tenth)

Length of fencing required = 8.9 + 7.1 + 7.2 + 11.4 = 34.6 units

8 0

2 years ago

Leon found the sum 5/6and2/3 to be 11/12. How can you tell that his answer is incorrect without calculating

VARVARA [1.3K]

First , in order to find the answer you need to add the add the numerators which are 5 and 2 = 7 and then you need to find a common denominator.

4 0

3 years ago

Read 2 more answers