Itś basically the same thing as a compare and contrast circle graph when they intersect with eachother
To find the 'maximum height' we will need to take the derivative of h(t) = –16t² + 32t + 6 then set it equal to zero, then solve for t. this t will be the time at which the ball reaches it's maximum height.
Answer:
option (D) is the right answer
Answer:
(st)(6)= s(6) * t(6)
Step-by-step explanation:
(st)(6)
(st)(x)= s(x) * t(x) we multiply it
(st)(6)= s(6) * t(6)
Hope this helps.
1/5 , 3/10 , 0.5
This will help
