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3 years ago

6

On an architect's blueprint, 1 inch corresponds to 8 feet. Find the length of a wall represented by a line 1 1/8 inches long on

the blueprint

2 answers:

zalisa [80]3 years ago

7 0

Answer:

Length = 1 1/8 x 8 = 9 ft

Step-by-step explanation:

Keith_Richards [23]3 years ago

4 0

The problem is simply asking as to convert the measurement from the smaller scale to the actual scale. For this, we simply multiply the factor to the smaller measurement. We do as follows:

Length = 1 1/8 x 8 = 9 ft

Hope this helps.

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Please help me solve this problem ASAP

DiKsa [7]

$\bold{\huge{\blue{\underline{ Solution }}}}$

<h3><u>Given </u><u>:</u><u>-</u></h3>

<u>The </u><u>right </u><u>angled </u><u>below </u><u>is </u><u>formed </u><u>by </u><u>3</u><u> </u><u>squares </u><u>A</u><u>, </u><u> </u><u>B </u><u>and </u><u>C</u>
<u>The </u><u>area </u><u>of </u><u>square </u><u>B</u><u> </u><u>has </u><u>an </u><u>area </u><u>of </u><u>1</u><u>4</u><u>4</u><u> </u><u>inches </u><u>²</u>
<u>The </u><u>area </u><u>of </u><u>square </u><u>C </u><u>has </u><u>an </u><u>of </u><u>1</u><u>6</u><u>9</u><u> </u><u>inches </u><u>²</u>

<h3><u>To </u><u>Find </u><u>:</u><u>-</u></h3>

<u>We </u><u>have </u><u>to </u><u>find </u><u>the </u><u>area </u><u>of </u><u>square </u><u>A</u><u>? </u>

<h3><u>Let's </u><u>Begin </u><u>:</u><u>-</u><u> </u></h3>

The right angled triangle is formed by 3 squares

<u>We </u><u>have</u><u>, </u>

Area of square B is 144 inches²
Area of square C is 169 inches²

<u>We </u><u>know </u><u>that</u><u>, </u>

$\bold{ Area \: of \: square = Side × Side }$

Let the side of square B be x

<u>Subsitute </u><u>the </u><u>required </u><u>values</u><u>, </u>

$\sf{ 144 = x × x }$

$\sf{ 144 = x² }$

$\sf{ x = √144}$

$\bold{\red{ x = 12\: inches }}$

Thus, The dimension of square B is 12 inches

<h3><u>Now, </u></h3>

Area of square C = 169 inches

Let the side of square C be y

<u>Subsitute </u><u>the </u><u>required </u><u>values</u><u>, </u>

$\sf{ 169 = y × y }$

$\sf{ 169 = y² }$

$\sf{ y = √169}$

$\bold{\green{ y = 13\: inches }}$

Thus, The dimension of square C is 13 inches.

<h3><u>Now, </u></h3>

It is mentioned in the question that, the right angled triangle is formed by 3 squares

The dimensions of square be is x and y

Let the dimensions of square A be z

<h3><u>Therefore</u><u>, </u><u>By </u><u>using </u><u>Pythagoras </u><u>theorem</u><u>, </u></h3>

<u>The </u><u>sum </u><u>of </u><u>squares </u><u>of </u><u>base </u><u>and </u><u>perpendicular </u><u>height </u><u>equal </u><u>to </u><u>the </u><u>square </u><u>of </u><u>hypotenuse </u>

<u>That </u><u>is</u><u>, </u>

$\bold{\pink{ (Perpendicular)² + (Base)² = (Hypotenuse)² }}$

<u>Here</u><u>, </u>

Base = x = 12 inches
Perpendicular = z
Hypotenuse = y = 13 inches

<u>Subsitute </u><u>the </u><u>required </u><u>values</u><u>, </u>

$\sf{ (z)² + (x)² = (y)² }$

$\sf{ (z)² + (12)² = (169)² }$

$\sf{ (z)² + 144 = 169}$

$\sf{ (z)² = 169 - 144 }$

$\sf{ (z)² = 25}$

$\bold{\blue{ z = 5 }}$

Thus, The dimensions of square A is 5 inches

<h3><u>Therefore</u><u>,</u></h3>

Area of square

$\sf{ = Side × Side }$

$\sf{ = 5 × 5 }$

$\bold{\orange{ = 25\: inches }}$

Hence, The area of square A is 25 inches.

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2 years ago

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malfutka [58]

Answer:

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Step-by-step explanation:

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2 years ago

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Find the area of the composite figure and round the nearest tenth

Monica [59]

Answer:

The area of the composite figure is 1360 ft.

Step-by-step explanation:

First, you should split up the composite figure into separate shapes.

So to find area of the triangle all the way on the left, you multiply base x height then divide by 2.

<u>30 x 34 = 1020 ÷ 2 = 520.</u>

Then, moving on to next shape, we can break up the trapezoid into a rectangle and a triangle.

To find area of the rectangle you multiply length x width.

<u>16 x 30 = 480.</u>

Finally, we have the last triangle right above the rectangle. Keep in mind that the rectangle does not have a length of 40!

You have to subtract 40 - 16 which equals 24.

<u>30 x 24 = 720 ÷ 2 = 360.</u>

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3 years ago

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Given: AOB is a right angle

Crazy boy [7]

The missing piece of information in the proof is that m∠DOA and m∠BOC are vertical opposite angles.

<h3>How to find vertically opposite angles?</h3>

We want to prove that m∠BOC = 90°.

We are given that m∠AOB is a right angle triangle. Thus;

m∠BOC must also be equal to 90°

Now, since m∠BOC and m∠AOB are right angles, then it means that we must equally say that m∠DOA and m∠BOC are vertical opposite angles and they are as such equal.

Thus, the missing piece of information in the proof is that m∠DOA and m∠BOC are vertical opposite angles.

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1 year ago

Evaluate -1 -(-z) where z = -2

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Answer:

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