Helppppppppppppppppppppppppppppppppppppppppppppppppp

Use a system of equations to solve this problem.Bronze is a mix, or alloy, of tin and copper. A metal worker needs 100 g of bron

d1i1m1o1n [39]

Answer:

x = 50 grs

y = 50 grs

Step-by-step explanation:

" x " is quantity of bronze of 5% tin

" y " is quantity of bronze of 45% tin

The worker needs 100 grs of bronze and this bronze must be 25% tin

The mathematical expression for the 100 grs condition is:

x + y = 100

And the The mathematical expression for the % condition is:

0,05*x + 0.45*y = 0,25 * ( x + y )

The system is:

x + y = 100

0,05*x + 0,45*y = 0,25* ( x + y )

Solving this system we get values of x and y

y = 100 - x

0,05*x + 0,45* ( 100 - x ) = 0,25 * ( x + 100 - x )

0,05*x + 45 - 0,45*x = 0,25*( 100 )

0,05*x + 45 - 0,45*x = 25

- 0,4*x = -45 + 25

x = 20/0,4 x = 50 grs

and y = 50 grs

8 0

3 years ago

If s store is selling boxes of pudding at 3 for $0.99,how much would 12 boxes cost

sweet [91]

Answer:

The cost price of 12 boxes of pudding is $3.96

Step-by-step explanation:

Given as :

The quantity of pudding boxes = 3

The cost price for 3 boxes = $0.99

Again ,

The quantity of pudding boxes = 12

Let The cost price for 12 boxes = $x

Now, According to question

<u>Using Unitary method</u>

∵ The cost price of 3 boxes of pudding = $0.99

or,The cost price of 1 boxes of pudding = $\dfrac{0.99}{3}$ = $0.33

∴The cost price of 12 boxes of pudding =$0.33 × 12

I.e x =$3.96

So,The cost price of 12 boxes of pudding = x =$3.96

Hence,The cost price of 12 boxes of pudding is $3.96 Answer

4 0

3 years ago

I REALLY need answers, like if you see this PLEASE answer it

lana [24]

-4, -1, 1, 3, 3.9, 3.999,

3 0

3 years ago

Jimmy loaded three bags of sand into his wheelbarrow. The bags weighed 24/12 lbs, 32/35 lbs, and 44/18 lbs. The total amount of

sasho [114]

The correct answer is 5 113/315

3 0

3 years ago

.

Sunny_sXe [5.5K]

The solutions of the equations are -1.3 and -7.7

Step-by-step explanation:

The quadratic formula of solving the quadratic equation

ax² + bx + c = 0, where a, b and c are constant is:

$x=\frac{-b+-\sqrt{b^{2}-4ac}}{2a}$

To solve the quadratic equation by using the quadratic formula

1. Find the values of a , b and c from the equation

2. Substitute the values of a , b and c in the quadratic formula

3. Find the two values of x

∵ x² + 9x + 10 = 0

∴ a = 1 , b = 9 and c = 10

∵ $x=\frac{-9+\sqrt{(9)^{2}-4(1)(10)}}{2(1)}$

∴ $x=\frac{-9+\sqrt{81-40}}{2}$

∴ $x=\frac{-9+\sqrt{41}}{2}$

∴ x = -1.3

∵ $x=\frac{-9-\sqrt{(9)^{2}-4(1)(10)}}{2(1)}$

∴ $x=\frac{-9-\sqrt{81-40}}{2}$

∴ $x=\frac{-9-\sqrt{41}}{2}$

∴ x = -7.7

The solutions of the equations are -1.3 and -7.7

Learn more:

You can learn more about quadratic equation in brainly.com/question/8196933

#LearnwithBrainly

6 0

3 years ago