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2 years ago

10

Frank is investing his money. He thinks that he should make $8 for every $100 he invests. How much does he expect to make on an

investment of $4300?

1 answer:

melisa1 [442]2 years ago

4 0

Answer:

537.5

Step-by-step explanation:

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Only answer 28 ( I added this parentheses so that the thing would accept my question)

avanturin [10]

Answer:

(a). Number of protons in a chlorine atom = 17

(b). Atomic number of sodium = 11

Step-by-step explanation:

Let the number of protons in a sodium atom = <em>x</em>

Then, the number of protons in a chlorine atom =<em> x</em> + 6

Now, it is given that the atomic number of an element is equal to the number of protons per atom.

So, atomic number of sodium (Na) = <em>x</em>

Atomic number of chlorine (Cl) = <em>x</em> + 6

It is given that the atomic number of chlorine is 5 less than twice the atomic number of sodium.

∴ atomic number of chlorine (Cl) = 2 × atomic number of sodium (Na) - 5

⇒ <em>x</em> + 6 = 2<em>x</em> - 5

⇒ <em>x </em>- 2<em>x</em> = -5 - 6

⇒ -<em>x</em> = -11

Cancelling the minus sign from both sides, we get

<em>x</em> = 11

(a). Number of protons in a chlorine atom = <em>x</em> + 6

= 11 + 6 (∵ <em>x</em> = 11)

= 17

(b). Atomic number of sodium = <em>x</em> = 11

3 0

2 years ago

Hi! ❤️ , im looking for some help here. ill give brainliest if able to.

olchik [2.2K]

Hello there! The solution of your question has been given below.

<h3>Solution:</h3>

${6}^{ - 2} \\ = ( \frac{1}{6} ) ^{2} \\ = \frac{ {1}^{2} }{ {6}^{2} } \\ = \frac{1}{36}$

<h3>Answer:</h3>

Option B.

$\frac{1}{36}$

5 0

2 years ago

Solve the following system of equations by substitution.<br> y=-1<br> 5x + 7y = -2

Nady [450]

Answer:

(1,-1)

Step-by-step explanation:

7 0

2 years ago

Determine whether the integral is convergent or divergent. [infinity] 7 e−1/x x2 dx convergent divergent Changed: Your submitted

inessss [21]

I suppose the integral could be

$\displaystyle\int_7^\infty\frac{e^{-1/x}}{x^2}\,\mathrm dx$

In that case, since $-\frac1x\to0$ as $x\to\infty$ , we know $e^{-1/x}\to1$ . We also have $\left(e^{-1/x}\right)'=\frac{e^{-1/x}}{x^2}>0$ , so the integral is approach +1 from below. This tells us that, by comparison,

$\displaystyle\frac{e^{-1/x}}{x^2}\le\frac1{x^2}\implies\int_7^\infty\frac{e^{-1/x}}{x^2}\,\mathrm dx\le\int_7^\infty\frac{\mathrm dx}{x^2}$

and the latter integral is convergent, so this integral must converge.

To find its value, let $u=-\frac1x$ , so that $\mathrm du=\frac{\mathrm dx}{x^2}$ . Then the integral is equal to

$\displaystyle\int_{-1/7}^0e^u\,\mathrm du=e^0-e^{-1/7}=1-\frac1{\sqrt[7]{e}}$

4 0

3 years ago

A wheelchair ramp has a slope of 1 10 . if its rise is 1 5 2 feet, what is its run?

ikadub [295]

$slope = \frac{rise}{run} \\ 110 = \frac{152}{run} \\ run \times 110 = 152 \\ run = \frac{152}{110} \\ run = \frac{76}{55} \: \: \: \: or \: \: \: 1.38$

7 0

2 years ago