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3 years ago

What is the surface area of 3in 11in 4in 5in triangular prism

Mathematics

1 answer:

zvonat [6]3 years ago

6 0

Answer:

Answer:

Step-by-step explanation:

The surface area of a rectangular prism is given by :-

Given: Length = 5 in.

Width = 5 in.

Height = 12 im.

Now, the surface area of the rectangular prism will be :-

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Llamando x a un numero, expresa en lenguaje algebraico su doble

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3 years ago

sin alpha = 7/25, alpha lies in quadrant ii, and cos beta = 2/5, beta lies in quadrant i. find cos(alpha-beta).

Ilia_Sergeevich [38]

Answer:

Therefore $\cos(\alpha-\beta)=\frac{48+7\sqrt{25}}{125}$

Step-by-step explanation:

Given values are

$\sin \alpha=\frac{7}{25}$

$\cos \beta=\frac{2}{5}$

$\sin^2x+\cos^2=1$

$\cos \alpha=\sqrt{1-\sin^2\alpha}$

$\cos \alpha=\sqrt{1-(\frac{7}{25})^2}$

$\cos \alpha=\sqrt{1-\frac{49}{625}}$

$\cos \alpha=\sqrt{\frac{576}{625}}$

$\cos \alpha=\frac{24}{25}$

$\sin \beta=\sqrt{1-\cos^2\beta}$

$\sin \beta=\sqrt{1-(\frac{2}{5})^2}$

$\sin \beta=\sqrt{1-\frac{4}{25}}$

$\sin \beta=\frac{\sqrt{21}}{5}$

$\cos(\alpha-\beta)=\cos\alpha\cos\beta+\sin\alpha\sin\beta$

$\cos(\alpha-\beta)=\frac{24}{25}\times\frac{2}{5}+\frac{7}{25}\times\frac{\sqrt{21}}{5}$

$\cos(\alpha-\beta)=\frac{48+7\sqrt{25}}{125}$

7 0

3 years ago

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stiks02 [169]

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Step-by-step explanation:

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3 years ago

AC if TC = 20q + 10q^2?

Alexus [3.1K]

Answer:

AC = (20+ 10q)

Step-by-step explanation:

Given that,

Total cost, TC = 20q + 10q²

We need to find AC i.e. average cost.

It can be solved as follows :

$AC=\dfrac{TC}{q}\\\\AC=\dfrac{20q + 10q^2}{q}\\\\AC=\dfrac{q(20+ 10q)}{q}\\\\AC={(20+ 10q)}$

So, the value of AC is (20+ 10q).

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3 years ago

a bag contains 6 black marbles and 6 white marbles. What is the least number of marbles that you must choose, without looking, t

o-na [289]

Given:

Number of black marbles = 6

Number of white marbles = 6

Let's determine the least number of marbles that can be chosen to be certain that you have chosen two marble of the same color.

To find the least number of marble to be chosen to be cartain you have chosen two marbles of the same color, we have:

Total number of marbles = 6 + 6 = 12

Number of marbles to ensure at least one black marble is chosen = 6 + 1 = 7

Number of marbles to ensure at least one white marble is chosen = 1 + 6 = 7

Therefore, the least number of marbles that you must choose, without looking , to be certain that you have chosen two marbles of the same color is 7.

ANSWER:

6 0

1 year ago