Answer:
(2, 5)
General Formulas and Concepts:
<u>Pre-Algebra</u>
Order of Operations: BPEMDAS
- Brackets
- Parenthesis
- Exponents
- Multiplication
- Division
- Addition
- Subtraction
Equality Properties
<u>Algebra I</u>
- Solving systems of equations using substitution/elimination
Step-by-step explanation:
<u>Step 1: Define Systems</u>
y - 3x = 1
2y - x = 12
<u>Step 2: Rewrite Systems</u>
y - 3x = 1
- Add 3x on both sides: y = 3x + 1
<u>Step 3: Redefine Systems</u>
y = 3x + 1
2y - x = 12
<u>Step 4: Solve for </u><em><u>x</u></em>
<em>Substitution</em>
- Substitute in <em>y</em>: 2(3x + 1) - x = 12
- Distribute 2: 6x + 2 - x = 12
- Combine like terms: 5x + 2 = 12
- Isolate <em>x</em> term: 5x = 10
- Isolate <em>x</em>: x = 2
<u>Step 5: Solve for </u><em><u>y</u></em>
- Define equation: 2y - x = 12
- Substitute in <em>x</em>: 2y - 2 = 12
- Isolate <em>y </em>term: 2y = 10
- Isolate <em>y</em>: y = 5
(5, 8) has two positive numbers. In case you don't remember
Quadrant I: Both positive
Quadrant II: Negative x value, Positive y value
Quadrant III: Both negative
Quadrant IV: Positive x value, Negative y value
5 and 8 are Both Positive, therefore it is in quadrant I.
Answer:
x = 3, 5
General Formulas and Concepts:
<u>Pre-Algebra</u>
Order of Operations: BPEMDAS
- Brackets
- Parenthesis
- Exponents
- Multiplication
- Division
- Addition
- Subtraction
Equality Properties
- Multiplication Property of Equality
- Division Property of Equality
- Addition Property of Equality
- Subtract Property of Equality
<u>Algebra I</u>
- Terms/Coefficients/Degrees
- Standard Form: ax² + bx + c = 0
- Multiple Roots
- Factoring
- Completing the Square: -b/(2a)
Step-by-step explanation:
<u>Step 1: Define</u>
x² - 8x + 15 = 0
<u>Step 2: Solve for </u><em><u>x</u></em>
- [Subtraction Property of Equality] Subtract 15 on both sides: x² - 8x = -15
- Complete the Square [Addition Property of Equality]: x² - 8x + 16 = -15 + 16
- [Complete the Square] Simplify: (x - 4)² = 1
- [Equality Property] Square root both sides: x - 4 = ±1
- [Addition Property of Equality] Add 4 on both sides: x = 4 ± 1
- Evaluate: x = 3, 5
Answer:
10 hours
Step-by-step explanation:
Say x is the number of hours he can rent the detector at most. Using it, we can set up this equation:
15 + 2x = 35
Subtract 15 from both sides
2x = 20
Divide by 2 on both sides
x = 10
Answer:
3 centimeters
Step-by-step explanation:
The diameter is 2 times the radius, meaning 6/2 is 3.
