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Ratling [72]
3 years ago
7

FIRST TO ANSWER GETS BRAINLIEST

Mathematics
2 answers:
Irina18 [472]3 years ago
6 0

proportions are just equivalent fractions

-5/-10 would be your answer =)

Zigmanuir [339]3 years ago
3 0

Answer:

The answer is 40,10 because if you look at the graph you can see the 1st number that the line land on is 10 then count down by 10s forward is 40 Hope this helps

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X/3+6-2x=-6 Please Help me I am stuck
nata0808 [166]

Answer:

x = 36/5

Step-by-step explanation:

Subtract 6 from both sides

x/3+6-2x-6 = -6-6

Simplify

x/3 - 2x = -12

Multiply both sides by 3

x/3 * 3 - 2x * 3 = -12 * 3

Simplify

-5x = -36

Divide both sides by -5

-5x/-5 = -36/-5

Simplify

x = 36/5

5 0
3 years ago
Find the slope of the line Y=6x-1/3
Arada [10]

Answer: the slope 6

Step-by-step explanation:

with the slope formula you can see the slope of the line right in the equation so therefore it is 6.

3 0
2 years ago
A triangle has sides lenghts of 6.8cm, 28.5cm and 29.3cm. is this a right angled triangle​
EleoNora [17]

Answer:

Yes it is a right angled triangle

Step-by-step explanation:

If its a right triangle it would satisfy the Pythagoras theorem.

29.3^2 = 858.49

28.5^2 = 812.25

6.8^2 =  46.24

Adding the last 2 values:

812.25 + 46.24

= 858.49

So YES.

6 0
2 years ago
If the length of segment RQ is 8, what is the length of segment PQ?
artcher [175]
Half of 8 is 4 so it’s b
7 0
3 years ago
We are interested in conducting a study to determine the percentage of voters of a state would vote for the incumbent governor.
Sidana [21]
Finding the sample size for estimating a population proportion.

The formula is:

n = (z/m)^2 p~(1−p~)

where:
Z is the z value of the confidence level where 95% is equal to 1.96

M is the margin of error where 0.05

And p~ is the estimated value of the proportion where it is 0.50

Solution:

n = (1.96/0.05)^2 (0.5) (1-0.5)

= 1.536.64 (0.5) (0.5)

= 768.32 (0.5)

= 384.16

This is the minimum sample size, therefore we should round it up to 385. The answer is letter c.
6 0
3 years ago
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