Answer:
(-4.666667, -3.16667)
Step-by-step explanation:
(-4 2/3, -3 1/6)
Answer:
Step-by-step explanation:
61 - (2 4/16 +3 2/3) = 61 - (5 +( 4/16 + 2/3))
= 61 - (5 +( 6/24 + 16/24))
= 61 - (5 + 22/24)
= (61 - 5) - 22/24
= 56 - 11/12
= 55 1/12
I surely don't have any clue on how to that type of math sorry.
Answer:
133/143
Step-by-step explanation:
Let S be the sample space
Let E be the event of selecting three committee partners with at least one junior partner.
Partners in the law firm include:
Senior partners = 6
Junior partners = 7
Total partners = 13
n(S) = number of ways of selecting 3 partners from 13 = 13C3
n(S) = 13C3 = 13!/(10!3!) = (13x12x11)/(3x2x1) = 286
To get n(E) i.e least 1 junior partner in the selected committee, we may have:
(2 senior and 1 junior) or ( 1 senior and 2 junior) or (3 junior).
Therefore, the required number of way is given below:
= (6C2 x 7C1) + (6C1 x 7C2) + 7C3
= [(6x5)/2 x 7] + [6 x (7x6)/2] + [(7x6x5)/(3x2)]
= 105 + 126 + 35
n(E) = 266
Therefore, the probability P(E) that at least one of the junior partners is on the committee is given below:
P(E) = n(E) /n(S)
P(E) = 266/286
P(E) = 133/143
3 equivalent ratios or 5/2
10 /4
20/8
30/12
