Answer:
Step-by-step explanation:
Given is an algebraic polynomial of degree 5.
Here leading term is p=3 and constant term is q =12
Factors of p are ±1,±2,±3
Factors of q are 
Possible forms of p/q will be the same for any other polynomial of degree 5 with leading term =3 and constant term = 12
Hence any other polynomial
will have same possible zeroes of p/q, when a,b,c are rational.
Hence any polynomial of this type would have the same possible rational roots.
Answer:
a5 = 2604
Step-by-step explanation:
a1 = 4
a2 = -5(4)-1 = -21
a3 =-5(-21)-1 = 104
a4 = -5(104)-1 =-521
a5 =-5(-521)-1 = 2604
To solve, you would need to make two equations and substitute one in for the other. Let a = # of adults, and c = # of children
5a + 2c = 1,220
a + c = 295
a + c = 295
-c -c
a = 295 - c
5(295 - c) + 2c = 1,220
1,475 - 5c + 2c = 1,220
1,475 - 3c = 1,220
1,475 - 3c = 1,220
-1,475 -1,475
-3c = -255
-3c/-3 = -255/-3
c = 85
a + c = 295
a + 85 = 295
-85 -85
a = 210
210 adults attended the dance recital
Hope this helps!
The square root of 75/3 is a irrational number
Answer:
x=-60
Step-by-step explanation:
