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Arte-miy333 [17]
3 years ago
8

Please please help i’ll give brainliest tysm:))

Mathematics
1 answer:
jenyasd209 [6]3 years ago
4 0

Answer:

70%

tell me if its wrong but this is what i got

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The midpoint of JK is M(4, 5). One endpoint is J(5,2). Find the coordinates of the other endpoint K.
Bogdan [553]

Answer:

9

Step-by-step explanation:

not 9

7 0
3 years ago
Please Need Help. Thank You :)<br><br><br>Please find the Volume of these cylinders:
vladimir2022 [97]

Answer:

the one for the finding the height is 3.3, the one with 7 as the height is 351.86, and the one with 3 as the height is 150.8

Step-by-step explanation:

h=V

πr2=41.5

π·22≈3.30247

V=πr2h=π·42·7≈351.85838

V=πr2h=π·42·3≈150.79645

4 0
3 years ago
Given f(x) =
sergejj [24]

Answer:

A

Step-by-step explanation:

We are given the function:

\displaystyle f(x) = \left\{        \begin{array}{ll}            2\cos(\pi x) \text{ for }  x \leq -1 \\ \\          \displaystyle   \frac{2}{\cos(\pi x)}\text{ for } x > -1        \end{array}    \right.

And we want to find:

\displaystyle \lim_{x\to -1}f(x)

So, we need to determine whether or not the limit exists. In other words, we will find the two one-sided limits.

Left-Hand Limit:

\displaystyle \lim_{x\to-1^-}f(x)

Since we are approaching from the left, we will use the first equation:

\displaystyle =\lim_{x\to -1^-}2\cos(\pi x)

By direct substitution:

=2\cos(\pi (-1))=2\cos(-\pi)=2(-1)=-2

Right-Hand Limit:

\displaystyle \lim_{x\to -1^+}f(x)

Since we are approaching from the right, we will use the second equation:

=\displaystyle \lim_{x\to -1^+}\frac{2}{\cos(\pi x)}

Direct substitution:

\displaystyle =\frac{2}{\cos(\pi (-1))}=\frac{2}{\cos(-\pi)}=\frac{2}{(-1)}=-2

So, we can see that:

\displaystyle \displaystyle \lim_{x\to-1^-}f(x)=\displaystyle \lim_{x\to -1^+}f(x) =-2

Since both the left- and right-hand limits exist and equal the same thing, we can conclude that:

\displaystyle \lim_{x \to -1}f(x)=-2

Our answer is A.

8 0
3 years ago
What is equivalent to p=2(I+w)
kicyunya [14]
P = 2L + 2W

This is called the distributive property.
5 0
3 years ago
For the same signal emitted by a radio antenna,
BlackZzzverrR [31]

Answer: The distance of  Observer A from the radio antenna is what fraction  of the distance of Observer B from the radio  antenna?​

It is 1/4.

Step-by-step explanation:

We know that the intensity of electromagnetic waves decreases with the radius squared, this means that we can write a simple relation as:

Intensity(r) = A/r^2

Observer A measures 16 the intensity of observer B.

if Ia is the intensity that observer A measures and Ib is the intensity that observer B measures, we have that:

Ia = 16Ib

A/(ra)^2 = 16*A/(rb)^2

1/(ra)^2 = 16/(rb)^2

rb^2 = 16*ra^2

and we know that 16 = 4*4 = 4^2

rb^2 = (4*ra)^2

then rb = 4*ra

this means that the distance between observer B and the antenna is equal to 4 times the distance between observer A and the antenna.

The fraction is ra = rb/4

The distance of

Observer A from the radio antenna is what fraction of the distance of Observer B from the radio antenna?​

It is 1/4.

4 0
4 years ago
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