n=3; We need a third degree polynomials with the following given zero's: 2 and 5i are zeros; f(-1)=156.
Since these are solutions
x = 2 ; x = 5i. Since imaginaries travel in pairs, the other answer is x= -5i.
We have (x-2)(x-5i)(x+5i) = 0
Now,
f(-1) = (-1-2)(-1-5i)(-1+5i) = 156.
f(-1) = (-3)(26) = -78.
But -78 x -2 = 156, so our polynomial becomes
Y= -2x (<em>x</em> - 2 ) x (<em>x </em>to the power of 2 + 25) = 0
Answer:
c 44
Step-by-step explanation:
Answer: 160
Step-by-step explanation:
Answer:
306 mi^2
Step-by-step explanation:
surface area = area of base + lateral area
surface area = s^2 + 4bh/2
surface area = (10 mi)^2 + 4(10 mi)(10.3 mi)/2
surface area = 306 mi^2
Answer:
so it would be 5-7 i sorry if wrong
Step-by-step explanation:
