Based on the given function, the equivalent function that best shows the x-intercepts on the graph is f(x) = (6x - 1)(6x + 1)
<h3>What are
equivalent functions?</h3>
Equivalent functions are different functions that have equal values when evaluated and compared
<h3>How to determin the equivalent function that best shows the x-intercepts on the graph?</h3>
The function is given as:
f(x) = 36x^2 - 1
Express 1 as 1^2
f(x) = 36x^2 - 1^2
Express 36x^2 as (6x)^2
f(x) = (6x)^2 - 1^2
Apply the difference of two squares.
This is represented as:
(a + b)(a - b) = a^2 - b^2
So, we have the following equation
f(x) = (6x - 1)(6x + 1)
Based on the given function, the equivalent function that best shows the x-intercepts on the graph is f(x) = (6x - 1)(6x + 1)
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Answer:
<h2>
</h2>
Step-by-step explanation:
Write all the numbers above the least common denominator 
Distribute 5 through the parentheses
Collect like terms
Hope this helps...
Good luck on your assignment...
<span>24x</span>³<span> - 54x</span>²<span> + 44x - 99 =
(24x</span>³ + 44x) - (54x² + 99) = <span>
4x</span>(6x²+11) - 9 (6x² + 11) =
(4x-9)(6x²+11)
Answer: (6x²+11)
Answer: A
<u>Step-by-step explanation:</u>
The vertical asymptote is the restriction on the x-value. Since the denominator cannot be equal to zero, then x + 1 ≠ 0 → x ≠ -1. So, the vertical asymptote is: x = -1
The horizontal asymptote is the restriction on the y-value. Since the degree of the numerator is less than the degree of the denominator, the horizontal asymptote is y = 0. However, there is a vertical shift of 2 units up so the horizontal asymptote is: y = 2
The only graph that displays these asymptotes is the first graph, <em>which I call graph A.</em>
