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Liula [17]
3 years ago
9

Need help to write equations for 5, 6 & 7

Mathematics
1 answer:
hoa [83]3 years ago
8 0
7)
Read my note at the end of problem 5 in another post.
You already know this table represents an exponential function
since each y-coordinate is always the previous y-coordinate multiplied by 6.
That means b = 6, and you have
y = a(6)^x
Now we find "a". When x = 0, y = 5. That means a = 5.
The equation is

y = 5(6)^x
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What is the value of X in the equation 3X (-1) / 9Y equals 18 when Y equal 27
iren [92.7K]

Answer:

The value of X in the equation 3X (-1) / 9Y equals 18 when Y equal 27 is 1458.33

Step-by-step explanation:

\frac{3X - 1}{9 Y} = 18 is a polinomial equation A

if the value of Y = 27

put this value of Y in the equation A

\frac{3 X -1}{9 \times 27} = 18

\frac{3 X -1}{243} = 18

243 will be taken to right hand side and as per rule will be multiplied by 18

3X-1= 18\times 243\\

3X-1= 4374

1 will be taken to right hand side and added as per rule

3 X = 4374+1\\3X= 4375

3 wil be taken on right hand side and divided as per rule

X= \frac{4375}{3} \\X= 1458.33

So the value of X if Y = 27 is 1458.33

Keywords:  Algebra

Learn more about Algebra at:

  • brainly.com/question/10710410
  • brainly.com/question/10708697

#learnwithBrainly

6 0
3 years ago
What does Sam need to score on the fourth test to ensure that she will have an average of 90% for all four tests?
olga_2 [115]

Answer:

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4 0
3 years ago
Write the equation of the circle with radius 2 and center (2,-3)
Luba_88 [7]

Answer:

(x-2)^{2} + (y+3)^{2} = 4

Step-by-step explanation:

Formula

Centre (a,b) \\Radius r(x-a)^{2} + (y-b)^{2} = r^{2}\\\\Centre (2, -3) \\Radius 2(x-(2))^{2} + (y-(-3))^{2} = 2^{2}\\(x-2)^{2} + (y+3)^{2} = 4

8 0
3 years ago
Evaluate the Riemann sum for (x) = x3 − 6x, for 0 ≤ x ≤ 3 with six subintervals, taking the sample points, xi, to be the right e
DENIUS [597]
Hello,

Reminders:
$\sum_{i=1}^{n} i= \dfrac{n(n+1)}{2}$



$ \sum_{i=1}^{n} i^2= \dfrac{n(n+1)}{2}$


$ \sum_{i=1}^{n} i^3= \dfrac{n^2(n+1)^2}{4} $


n=6\\
x_{0}=0\\
x_{n}=3\\
\Delta= \dfrac{x_n-x_0}{n}=0.5\\


x_{i} =0+\Delta*i= \frac{i}{2}

$ \sum_{i=1}^{n}\ \Delta*f(x_{i})=\sum_{i=1}^{6}\  \dfrac{i^3/8-6i}{2} $
$= \dfrac{1}{2}\sum_{i=1}^{6}  (\frac{i^3}{8} -6i)=\dfrac{1}{16}*\frac{(6*7)^2}{4}- \frac{9*7}{2}= -3.9575


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8 0
3 years ago
Read 2 more answers
Fill in the blank (no word bank)
anastassius [24]

Answer:

1.Angle B

2.Angle C

If It Is Wronge Sory

8 0
3 years ago
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