Speed is expressed as the ratio of distance/time = d/t
in Alex's case, speed = (3.8 miles / 18 minutes)
. . . or simply
3.8/18
Answer:
Step-by-step explanation:
-1, - 0.6, - (2/5), - (1/4), - (1/5), 0, 0.2, 0.25, 0.4, (3/4), (4/5), 1
I hope I've helped you.
Answer:
The solution is (2,6)
Step-by-step explanation:
Let
x-----> the number of hours to change a fuel injection unit
y-----> the number of hours to change a transmission
we know that
5x+10y=70 -----> equation A
8x+8y=64 -----> equation B
Solve the system of equations by graphing
Remember that the solution of the system of equations is the intersection point both graphs
The solution is the point (2,6)
see the attached figure
Given that <span>For
a certain model of car the distance
![d](https://tex.z-dn.net/?f=d)
required to stop the vehicle if
it is traveling at
![v](https://tex.z-dn.net/?f=v)
mi/h is given by the formula
![d=v+\frac{v^2}{20}, where [tex]d](https://tex.z-dn.net/?f=d%3Dv%2B%5Cfrac%7Bv%5E2%7D%7B20%7D%2C%20where%20%5Btex%5Dd%20)
is measured in feet.
If Kerry wants her stopping distance not to exceed 75
ft, then the range of speeds (in mi/h) can she travel is obtained as follows:
![v+ \frac{v^2}{20} \leq75 \\ \\ 20v+v^2\leq1,500 \\ \\ v^2+20v+100\leq1,500+100 \\ \\ (v+10)^2\leq1,600 \\ \\ |v+10|\leq\sqrt{1,600} \\ \\ -40\leq v+10\leq40 \\ \\ -40-10\leqv\leq v\leq40-10 \\ \\ -50\leq v\leq30](https://tex.z-dn.net/?f=v%2B%20%5Cfrac%7Bv%5E2%7D%7B20%7D%20%5Cleq75%20%5C%5C%20%20%5C%5C%2020v%2Bv%5E2%5Cleq1%2C500%20%5C%5C%20%20%5C%5C%20v%5E2%2B20v%2B100%5Cleq1%2C500%2B100%20%5C%5C%20%20%5C%5C%20%28v%2B10%29%5E2%5Cleq1%2C600%20%5C%5C%20%20%5C%5C%20%7Cv%2B10%7C%5Cleq%5Csqrt%7B1%2C600%7D%20%5C%5C%20%20%5C%5C%20-40%5Cleq%20v%2B10%5Cleq40%20%5C%5C%20%20%5C%5C%20-40-10%5Cleqv%5Cleq%20v%5Cleq40-10%20%5C%5C%20%20%5C%5C%20-50%5Cleq%20v%5Cleq30)
Therefore, the range of speed she can travel is
![v\leq30\ mi/hr](https://tex.z-dn.net/?f=v%5Cleq30%5C%20mi%2Fhr)
</span>
The answer to this problem is 4