Answer:
∠CBJ ≅ ∠ DHG
∠ FJH ≅ ∠ AJB
m∠JAB=75°
m∠JBC=130°
Step-by-step explanation:
Please refer to the image uploaded with this answer.
Here we are given two parallel line C and D and two transverses to them E and G , there by forming a number of angles. Before answering them we must under stand the characteristics of the angles formed by them and the various properties of them. For that please refer to the image attached,
i) we are asked to find the congruent angle to ∠CBJ has a corresponding angle names as ∠ DHG. And corresponding angles are same so ∠CBJ ≅ ∠ DHG
ii) Also ∠ FJH ≅ ∠ AJB , as they are vertically opposite angles and vertically opposite angles are equal.
iii) m∠EFD =75°
m∠EFD ≅ m∠JAB=75° ( corresponding angles )
iv) m∠GHF=130°
m∠GHF=m∠JBC=130° ( corresponding angles )
Answer:
x = 9, y = 29 or (8,29)
Step-by-step explanation:
Set the equations equal to each other because they both equal y:
4x - 3 = 2x + 13
Combine like terms:
2x = 16
Divide by 2:
x = 8
Plug 8 into the x for both equations and see if the y is the same:
y = 4(8) - 3 = 32 - 3 = 29
y = 2(8) + 13 = 16 + 13 = 29
If you use BEDMAS you should end up with an answer of 1004.
We know that the side lengths of the square base are: x * x. The volume is 12, so for now, let's say that y is the other side length. Then, x * x * y = 12. We can solve for y: y = 12/x^2. Now, we find the surface area of the 5 sides.
Four of the sides have the same area: x * (12/x^2) = 12/x, so we multiply this by 4: 48/x.
The last side is the base: x * x = x^2.
We add 48/x to x^2:
x^2 + 48/x
So, the answer is the fourth choice, (d).
Answer:
60
Step-by-step explanation:
The computation of the rest of the marbles is given below:
Since there is 20 red and 15 white marbles
Also the 3 bags contains same marbles
So if he gives 45 marbles, so the remaining would be
= (20 + 15) × 3 - 45
= 35 × 3 - 45
= 105 - 45
= 60
