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2 years ago

Please answer this I will give brainliest if you answer right first.

Mathematics

1 answer:

Vesnalui [34]2 years ago

3 0

Answer:

k = 5; y = 5x

Step-by-step explanation:

The constant of proportionality is the value of y/x. Picking a random value on the graph, such as (2, 10), we can substitute this into the formula for k = y/x. 10/2 = 5. This satisfies one portion of the answer. Now, if we take the value of x from the same point, (2, 10), which is 2, and multiply it by 5, as illustrated in y = 5x, we get 10 for y. This suits the equation as mentioned and we can check other points with the same process to ensure that this answer is correct.

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Bentley is going to invest $98,000 and leave it in an account for 7 years. Assuming

den301095 [7]

Answer:

The rate of interest for compounded daily is 2.1 6

Step-by-step explanation:

Given as :

The principal investment = $ 98,000

The Time period for investment = 7 years

Let The rate of interest compounded daily = R %

The Amount at the end up = $ 114,000

From compounded method

Amount = Principal × $(1+\dfrac{rate}{365\times 100})^{365\times Time}$

Or, $ 114,000 = $ 98,000 × $(1+\dfrac{R}{365\times 100})^{365\times 7}$

Or, $\frac{114000}{98000}$ = $(1+\dfrac{R}{36500})^{2555}$

or, 1.16326 = $(1+\dfrac{R}{36500})^{2555}$

or, $(1.16326)^{\frac{1}{2555}}$ = 1 + $\frac{R}{36500}$

1.00005919 - 1 = $\frac{R}{36500}$

or, 0.00005919 = $\frac{R}{36500}$

∴ R = 0.00005919 × 365000 = 2.16

Hence the rate of interest for compounded daily is 2.1 6 Answer

4 0

3 years ago

What is 43.043 in expanded form

nordsb [41]

40+3+.04+.003

expanded form is showing what you have to add together

3 0

3 years ago

A survey of 200 students is selected randomly on a large university campus. They are asked if they use a laptop in class to take

Lina20 [59]

Answer:

The 95% confidence interval for the true proportion of university students who use laptop in class to take notes is (0.2839, 0.4161).

Step-by-step explanation:

The (1 - α)% confidence interval for population proportion P is:

$CI=p\pm z_{\alpha/2}\sqrt{\frac{p(1- p)}{n}}$

The information provided is:

x = number of students who responded as"yes" = 70

n = sample size = 200

Confidence level = 95%

The formula to compute the sample proportion is:

$p=\frac{x}{n}$

The R codes for the construction of the 95% confidence interval is:

> x=70

> n=200

> p=x/n

> p

[1] 0.35

> s=sqrt((p*(1-p))/n)

> s

[1] 0.03372684

> E=qnorm(0.975)*s

> lower=p-E

> upper=p+E

> lower

[1] 0.2838966

> upper

[1] 0.4161034

Thus, the 95% confidence interval for the true proportion of university students who use laptop in class to take notes is (0.2839, 0.4161).

7 0

3 years ago

Read 2 more answers

They make a base of 50 gallons (20%). They make a “heavy batch of 150 gallons (80%) They mix them both. What is the percent of

SSSSS [86.1K]

Answer #1: x= 250

50 = x times 20/100

X= 100 times 50/ 20

X=250

Answer #2: same explanation but the answer is X= 120

If your talking about merging the percentage of the answer, I can’t help you with that

4 0

2 years ago

Read 2 more answers

(b) A department store has 7,000 charge accounts. The comptroller takes a random sample of 36 of

galben [10]

Answer:

a.0.8664

b. 0.23753

c. 0.15866

Step-by-step explanation:

The comptroller takes a random sample of 36 of the account balances and calculates the standard deviation to be N42.00. If the actual mean (1) of the account balances is N175.00, what is the probability that the sample mean would be between

a. N164.50 and N185.50?

b. greater than N180.00?

c. less than N168.00?

We solve the above question using z score formula

z = (x-μ)/σ/√n where

x is the raw score,

μ is the population mean = N175

σ is the population standard deviation = N42

n is random number of sample = 36

a. Between N164.50 and N185.50?

For x = N 164.50

z = 164.50 - 175/42 /√36

z = -1.5

Probability value from Z-Table:

P(x = 164.50) = 0.066807

For x = N185.50

z = 185.50 - 175/42 /√36

z =1.5

Probability value from Z-Table:

P(x=185.50) = 0.93319

Hence:

P(x = 185.50) - P(x =164.50)

= 0.93319 - 0.066807

= 0.866383

Approximately = 0.8664

b. greater than N180.00?

x > N 180

Hence:

z = 180 - 175/42 /√36

z = 5/42/6

z = 5/7

= 0.71429

Probability value from Z-Table:

P(x<180) = 0.76247

P(x>180) = 1 - P(x<180) = 0.23753

c. less than N168.00?

x < N168.

z = 168 - 175/42 /√36

z = -7/42/6

z = -7/7

z = -1

Probability value from Z-Table:

P(x<168) = 0.15866

4 0

2 years ago