All large radioactive atoms decay into smaller atoms by emitting alpha particles which consists of two protons and two neutrons. An alpha particle can also be thought of as the nucleus of a helium atom and as such they are sometimes referred to as He2+ . The positive charge is due to the lack of two electrons.

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A locus that affects susceptibility to a degenerative brain disease has two alleles, V and v. In a population, 16 people have ge

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Answer:

Yes, the population is evolving

Explanation:

Hardy-Weinberg equilibrium states that a population is not evolving if it is in hardy weinberg equilibrium as the alleles frequency do not change over time in generations.

In mathematical equation, the genotype frequency will be -P²+2Pq+q²=1 and allele frequency will be p+q=1, where p = dominant allele and q will be recessive allele.

In the question, since the observed genotype are-

P² - VV= 16

2Pq- Vv- 92

q²- vv- 12

1. Calculate allele frequency

Now we will calculate if the expected value is same or close or not.

We will calculate allele frequency

Population has 120 individuals which means it has - 240 alleles.

In which V (p) will be- 32 +92= 124 allele

p- dominant allele/ total allele= 124/ 240 = 0.52

P= 0.52

q will be 1-0.52= 0.48

2. Expected genotype frequency

Now we will calculate expected genotypic frequency.

P²- 0.52 X 0.52= 0.27

2Pq = 2 x 0.52x 0.48 = 0.5

q²= 0.48 x 0.48 = 0.23

3. Expected progeny

P²= 0.27 x 120= 32 VV

2Pq= 0.5 X 120= 60 Vv

q²= 0.23 x 120= 28 vv

Since the observed value is not equal to the expected value therefore the population is not in Hardy- Weinberg equilibrium and the population is evolving.

Thus, Yes, the population is evolving is correct.

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