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4 years ago

Solving for Y. Write the slope-intercept form of the equation of each line. Show work!

Mathematics

1 answer:

Alborosie4 years ago

3 0

Answer:

y = x-4

Step-by-step explanation:

you can put it in a calculator to be sure

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Please help!!!! Chris is a fitness instructor.

dmitriy555 [2]

Answer:

i think its d

Step-by-step explanation:

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3 years ago

Can u guys help me with number one plz<br>

attashe74 [19]

Answer:

Step-by-step explanation:

8 0

3 years ago

Whats is the answer to this question below?

uysha [10]

Hey there. So first we need to know what the point slope form looks like.

It is Y-Y1=M (X-X1)

Knowing this you just plug in the given information.

M is equal to 1/6. So in this case all of the options have the correct m. Next we look at the Year value. We know Y is a positive 4. So the beginning of the equation is going to look like

Y+4=1/6 ( X-X1).

Nown plug in x. It would be a negative 5. Now your final answer would be option A. Hope the explanation helped.. :)

4 0

3 years ago

Please help ive been stuck on this question.

RUDIKE [14]

The value of the expression 8 / m - 11 / 3m is 13 / 3m

<h3 /><h3>How to simplify an expression?</h3>

8 / m - 11 / 3m

Therefore,

8 / m - 11 / 3m

The factor of the denominator is 3m

Therefore,

8 / m - 11 / 3m = 3(8) - 11/ 3m

3(8) - 11/ 3m = 24 - 11 / 3m

24 - 11 / 3m = 13 / 3m

learn more on fraction here: brainly.com/question/24161414

#SPJ1

7 0

2 years ago

If there are 52 cards in a deck with four suits (hearts, clubs, diamonds, and spades), how many ways can you select 5 diamonds a

Luba_88 [7]

Answer:

$12C5 *(12C3) = 792*220 =174240 ways$

Step-by-step explanation:

For this case we know that we have 12 cards of each denomination (hearts, diamonds, clubs and spades) because 12*4= 52

First let's find the number of ways in order to select 5 diamonds. We can use the combinatory formula since the order for this case no matter. The general formula for combinatory is given by:

$nCx = \frac{n!}{x! (n-x)!}$

So then 12 C5 would be equal to:

$12C5 = \frac{12!}{5! (12-5)!}=\frac{12!}{5! 7!} = \frac{12*11*10*9*8*7!}{5! 7!}= \frac{12*11*10*9*8}{5*4*3*2*1}=792$

So we have 792 was in order to select 5 diamonds from the total of 12

Now in order to select 3 clubs from the total of 12 we have the following number of ways:

$12C3 = \frac{12!}{3! 9!}=\frac{12*11*10*9!}{3! 9!} =\frac{12*11*10}{3*2*1}=220$

So then the numbers of ways in order to select 5 diamonds and 3 clubs are:

$(12C5)*(12C3) = 792*220 =174240 ways$

3 0

3 years ago