What is the equation of the line perpendicular to y=1/2x+6 that passes through points 4,1

Which of the following is the net of a pyramid?

Masja [62]

Answer:

The answer is A

Step-by-step explanation: a net of a pyramid will always have a square and 4 triangles around it.

4 0

3 years ago

Plz help meeeeeeeee You must make a constructive response and this is 8th Grade Math

Natali [406]

Answer:

I'm in 10th grade so I'll see what I can do and will answer to the best of my ability.

Step-by-step explanation:

What Julie did wrong was, she did simplify she just did it wrong. She used 4*8 which does equal 32 but 8 can't be simplified anymore than that. If she would of used 2*16 then her answer would be right.

Hope this helps!

7 0

3 years ago

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The probability that a company will launch the product A and B are 0.45 and 0.60 respectively, in main while, probability that b

Brrunno [24]

Answer:

a) what is the probability that Neither will of these products launch ?

= 0.30

b) At least one product will be launched ?

= 0.70

Step-by-step explanation:

From the above question, we have the following information:

P(A) = 0.45

P(B) = 0.60

P(A ∩ B) = P(A and B) launching = 0.35

Step 1

We find the Probability that A or B will launch

P (A ∪ B) = P(A) + P(B) - P(A ∩ B)

= 0.60 + 0.45 - 0.35

= 1.05 - 0.35

= 0.70

a) what is the probability that Neither will of these products launch ?

1 - Probability ( A or B will launch)

= 1 - 0.70

= 0.30

b)At least one product will be launched?

This is equivalent to the probability that A or B will be launched

P (A ∪ B) = P(A) + P(B) - P(A ∩ B)

= 0.60 + 0.45 - 0.35

= 1.05 - 0.35

= 0.70

3 0

3 years ago

An 8-sided die is formed when two square pyramids are attached by their bases. The perimeter of the base shape is 6 centimeters.

bogdanovich [222]

1. Check the picture attached. Consider the half of the 8-sided die, that is the pyramid ABCDE:

2. The perimeter of the base is 6, so each side of the base is 6/4=3/2

3. The distance between the tallest points is 2 cm, si the height of Pyramid ABCDE is 1 cm.

4. Consider the right triangle EOM in the figure:

EO=1, OM= 3/4 (it is half of AB=3/2) and EM is the hypothenuse, so by the pythagorean theorem length of EM is $\sqrt{1+ ( \frac{3}{4} )^{2} }= \sqrt{1+ \frac{9}{16} }= \sqrt{ \frac{25}{16} }= \frac{5}{4}$ (cm)

5. So side EBC has area
$\frac{1}{2}BC*EM= \frac{1}{2}* \frac{3}{2}* \frac{5}{4}= \frac{15}{16}$

6. The total area is 8*Area(EBC)= $8* \frac{15}{16}= \frac{15}{2}=7.5 ( cm^{2} )$

6 0

3 years ago

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48. Calculate the value of c in the triangle below.

guapka [62]

Answer:

17

Step-by-step explanation:

c = a^2 + b^2 = 15^2 + 8^2 = 17

6 0

3 years ago

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