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kenny6666 [7]
2 years ago
8

Joe has 6 frogs, 8 hamsters, 9 goldfish, and 3 snakes. What is the ratio of Joe's frogs and snakes to hamsters?

Mathematics
2 answers:
SVEN [57.7K]2 years ago
8 0

Answer:

9:8

Step-by-step explanation:

According to the word problem, Joe has 6 frogs, 8 hamsters, 9 goldfish, and 3 snakes.

The question is asking the ratio of Joe's frogs AND snakes TO hamsters.

To find out the ratio of frogs and snakes, add how many frogs there are to how many snakes there are.

6 + 3 = 9.

The last part of the equation should be obvious.

There are 8 hamsters.

Therefore, the ratio of Joe's frogs and snakes to hamsters is 9:8.

Morgarella [4.7K]2 years ago
6 0

Answer:

6:3:8

Step-by-step explanation:

We need to find the amount of:

Frogs= Joes has 6

Snakes= Joe has 3

Hamster= Joe has 8

So, the ratio of Joe's frogs and snakes to hamsters is 6: 8 : 3.

Hope that helped! :)

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Answer:

cooper has 14 goldfish

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because cooper has 2 times as many as Nando (2) and Jill (5) combined so 7 ( 5+2) times 2 is 14. 14 goldfish

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What are the coordinates (x, y) at which the graphs of 3.6x − 2y = 6 and −2.7x + y = 3 intersect? Round to the nearest tenth if
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3.6x - 2y = 6
-2.7x + y = 3.....multiply by 2
----------------
3.6x - 2y = 6
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The number of bagels sold daily for two bakeries is shown in the table. Bakery A Bakery 45, 52, 51, 48, 57, 30, 55, 46 Bakery B
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An Archer shoots an arrow horizontally at 250 feet per second. The bullseye on the target and the arrow are initially at the sam
Genrish500 [490]

Answer:

<h2>1.84feet</h2>

Step-by-step explanation:

Using the formula for finding range in projectile, Since range is the distance covered in the horizontal direction;

Range R = U\sqrt{\frac{H}{g} }

U is the velocity of the arrow

H is the maximum height reached = distance below the bullseye reached by the arrow.

R is the horizontal distance covered i.e the distance of the target from the archer.

g is the acceleration due to gravity.

Given R = 60ft, U = 250ft/s, g = 32ft/s H = ?

On substitution,

60 = 250\sqrt{\frac{H}{32}} \\\frac{60}{250} = \sqrt{\frac{H}{32}}\\\frac{6}{25} = \sqrt{\frac{H}{32}

Squaring both sides we have;

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The arrow will hit the target 1.84feet below the bullseye.

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