3 years ago

Joe has 6 frogs, 8 hamsters, 9 goldfish, and 3 snakes. What is the ratio of Joe's frogs and snakes to hamsters?

Mathematics

2 answers:

SVEN [57.7K]3 years ago

8 0

Answer:

9:8

Step-by-step explanation:

According to the word problem, Joe has 6 frogs, 8 hamsters, 9 goldfish, and 3 snakes.

The question is asking the ratio of Joe's frogs AND snakes TO hamsters.

To find out the ratio of frogs and snakes, add how many frogs there are to how many snakes there are.

6 + 3 = 9.

The last part of the equation should be obvious.

There are 8 hamsters.

Therefore, the ratio of Joe's frogs and snakes to hamsters is 9:8.

Morgarella [4.7K]3 years ago

6 0

Answer:

6:3:8

Step-by-step explanation:

We need to find the amount of:

Frogs= Joes has 6

Snakes= Joe has 3

Hamster= Joe has 8

So, the ratio of Joe's frogs and snakes to hamsters is 6: 8 : 3.

Hope that helped! :)

You might be interested in

Helpppppppppppppppppppppppppppppp

Alexxx [7]

The answer would be c

7 0

3 years ago

Read 2 more answers

Help me out:)i need an answer as soon as possible!!!

kifflom [539]

Answer is c , got it right

5 0

3 years ago

the building on the poster is 36cm tall. is it possible to figure out how tall the building is on the photograph?if its possible

fiasKO [112]

No because the stupidity of you can not calculate

4 0

3 years ago

The lifetime of a machine part has a continuous distribution on the interval (0, 50) with probability density function f, whe

Strike441 [17]

Answer:

Probability that the lifetime of the machine part is less than 13 = 0.6782

Step-by-step explanation:

given that $f(x)=(10+x)^{-2}$

Normalizing the function we get

$\int_{0 }^{50}cf(x)dx=1$

$\int_{0 }^{50}c(10+x)^{-2}dx=1$

$\therefore a=\frac{1}{\int_{0 }^{50}(10+x)^{-2}dx}$

$\therefore a=12$

$P(x< 13)=\int_{0}^{13}12(10+x)^{-2}dx\\\\P(X< 13)=0.6782$

4 0

3 years ago

What is the decrease of a right angle pls help i suck at math NVM ITS 90

Nookie1986 [14]

Answer: 90 degrees

Step-by-step explanation:

7 0

3 years ago