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kenny6666 [7]
3 years ago
8

Joe has 6 frogs, 8 hamsters, 9 goldfish, and 3 snakes. What is the ratio of Joe's frogs and snakes to hamsters?

Mathematics
2 answers:
SVEN [57.7K]3 years ago
8 0

Answer:

9:8

Step-by-step explanation:

According to the word problem, Joe has 6 frogs, 8 hamsters, 9 goldfish, and 3 snakes.

The question is asking the ratio of Joe's frogs AND snakes TO hamsters.

To find out the ratio of frogs and snakes, add how many frogs there are to how many snakes there are.

6 + 3 = 9.

The last part of the equation should be obvious.

There are 8 hamsters.

Therefore, the ratio of Joe's frogs and snakes to hamsters is 9:8.

Morgarella [4.7K]3 years ago
6 0

Answer:

6:3:8

Step-by-step explanation:

We need to find the amount of:

Frogs= Joes has 6

Snakes= Joe has 3

Hamster= Joe has 8

So, the ratio of Joe's frogs and snakes to hamsters is 6: 8 : 3.

Hope that helped! :)

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I believe the answer is D. Rectangular prism

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lara [203]

Hello from MrBillDoesMath!

Answer:

Top line: y = (2/3)x + 2

Bottom line:  y = (2/3)x  -1

Discussion:

The graph provided is hard to read but I did the best I could.

The top line appears to pass through the points (0,2) and (-3,0)

For this line

m =  change y /change x = (0-2)/(-3-0) = -2/-3 = +2/3. So

y = mx + b => y = (2/3) x+ b.  As the line passes through (0,2) set x = 0, y= 2 in y = (2/3)x + b =>  

2 = (2/3) 0 + b   => b = 2

Therefore    y = (2/3)x + 2

The bottom line appears to pass through the points (0,-1) and (3,1)

For this line

m =  change y /change x = (1-(-1)) /(3-0) = +2/-3. So

y = mx + b => y = (2/3) x+ b.  As the line passes through (0,-1) set x = 0, y= -1  in y = (2/3)x + b =>  

-1  = (2/3) 0 + b   => b = -1

Therefore    y = (2/3)x + -1

Thank you,

MrB

5 0
3 years ago
What is the equation of the line connecting (1,5) and (4,14)?
german
To find the slope of the line:
(y2-y1)/(x2-x1)
(14-5)/(4-1)=(9)/(3)=3

Only one of your 4 possible answers has 3 as a slope. However, plugging in each point into the y=mx+b equation, the y-intercept consistently comes out as 2..
y=mx+b
14=3(4)+b  b=2
5=3(1)+b    b=2
y=3x+2
If there is a consistent, positive slope (from your question, this does not seem to have a quadratic as an option), 3x+5 is not even a viable solution because x=1 when the y-value is 5 (and thus no other x value {0} could have a y-value of 5). It seems as though you have a typo on your hands. Hopefully this helps?
3 0
3 years ago
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