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3 years ago

6

the building on the poster is 36cm tall. is it possible to figure out how tall the building is on the photograph?if its possible

how so,if its not how not?

1 answer:

fiasKO [112]3 years ago

4 0

No because the stupidity of you can not calculate

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A collection of nickels and dimes is worth $9.45. If the number of dimes is doubled, the value is

eduard

Answer:

The number of nickels is 45 and the number of dimes is 72.

Step-by-step explanation:

Let

x ----> number of nickels

y ----> number of dimes

Remember that

$1\ nickel=\$0.05$

$1\ dime=\$0.10$

so

$0.05x+0.10y=9.45$ ------> equation A

$0.05x+0.10(2y)=16.65$

$0.05x+0.20y=16.65$ ------> equation B

<em>Solve the system by substitution</em>

we have

$0.05x+0.10y=9.45$ ------> equation A

$0.05x+0.20y=16.65$ ------> equation B

Multiply both equations by 100 both sides

$5x+10y=945$ ----> $5x=945-10y$ --> equation C

$5x+20y=1,665$ ----> equation D

substitute equation C in equation D

$(945-10y)+20y=1,665$

solve for y

$945+10y=1,665$

$10y=1,665-945$

$10y=720$

$y=72\ dimes$

Find the value of x

$5x=945-10y$

$5x=945-10(72)$

$5x=225$

$x=45\ nickels$

<em>Alternative Method</em>

Solve the system by graphing

Remember that the solution is the intersection point both graphs

using a graphing tool

the solution is the point (45,72)

therefore

The number of nickels is 45 and the number of dimes is 72.

7 0

3 years ago

The core melt- down and explosions at the nuclear reactor in Chernobyl in 1986 released large amounts of strontium-90, which dec

elena-14-01-66 [18.8K]

If $S(t)$ is the amount of strontium-90 present in the area in year $t$ , and it decays at a rate of 2.5% per year, then

$S(t+1)=(1-0.025)S(t)=0.975S(t)$

Let $S(0)=s$ be the starting amount immediately after the nuclear reactor explodes. Then

$S(t+1)=0.975S(t)=0.975^2S(t-1)=0.975^3S(t-2)=\cdots=0.975^{t+1}S(0)$

or simply

$S(t)=0.975^ts$

So that after 50 years, the amount of strontium-90 that remains is approximately

$S(50)=0.975^{50}s\approx0.282s$

or about 28% of the original amount.

We can confirm this another way; recall the exponential decay formula,

$S(t)=se^{kt}$

where $t$ is measured in years. We're told that 2.5% of the starting amount $s$ decays after 1 year, so that

$0.975s=se^k\implies k=\ln0.975$

Then after 50 years, we have

$S(50)=se^{50k}\approx0.282s$

5 0

3 years ago

One metre of ribbon costs $0.45. If Tabitha buys 225 metres of ribbon, how much will she have to pay? (Please help me! I have to

tatuchka [14]

Answer: $101.25

Step-by-step explanation:

Since we are given the information that one metre of ribbon costs $0.45 and that Tabitha buys 225 metres of ribbon, the amount that she will have to pay will be gotten by multiplying the cost of one meter of ribbon by the total meters that she bought. This will be:

= $0.45 × 225

= $101.25

Therefore, the cost is $101.25

6 0

3 years ago

Please help me i know its a hard question but please help i need the answer asap

Temka [501]

Answer:

1. Angle ABC = Angle DEF

2. Angle BCA = Angle EFD

3. Segment AC = Segment DF

4. Segment BA = Segment ED

7 0

3 years ago

A shoreline is eroding at a rate of 1/3 3 foot per 3 months. How many feet are eroding per year?

salantis [7]

7ft if 3+1/3 hopefully this helps i did hwat i can

4 0

4 years ago

Read 2 more answers