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Sidana [21]
3 years ago
12

I need to solve this problem

Mathematics
1 answer:
pentagon [3]3 years ago
5 0
The top would the width, the 7. would be height and the last would be the lemgth
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Does the function satisfy the hypotheses of the Mean Value Theorem on the given interval? f(x) = 3x2 − 2x + 1, [0, 2] Yes, it do
expeople1 [14]

Answer:

Yes , function is continuous in [0,2] and is differentiable (0,2) since polynomial function are continuous and differentiable

Step-by-step explanation:

We are given the Function

f(x) =3x^2 -2x +1

The two basic hypothesis of the mean valued theorem are

  • The function should be continuous in [0,2]
  • The function should be differentiable in (1,2)

upon checking the condition stated above on the given function

f(x) is continuous in the interval [0,2] as the functions is quadratic and we  can conclude that from its graph

also the f(x) is differentiable in (0,2)

f'(x) = 6x - 2

Now the function satisfies both the conditions

so applying MVT

6x-2 = f(2) - f(0) / 2-0

6x-2 = 9 - 1 /2

6x-2 = 4

6x=6

x=1

so this is the tangent line for this given function.

   

4 0
2 years ago
X 1/2 rational exponent
Lesechka [4]

Answer:

Step-by-step explanation:

Ok

7 0
3 years ago
Divide. check your answer
slava [35]

Step-by-step explanation:

:)..................

7 0
2 years ago
Five men and 5 women are ranked according to their scores on an examination. Assume that no two scores are alike and all possibl
serg [7]

Answer:

P(X=i) where i = 1,2,3,4,5,6,7,8,9,10 = 1/2, 5/18, 5/36, 5/84, 5/252, 1/252, 0, 0, 0, 0.

Step-by-step explanation:

X denotes the highest ranking achieved by the woman.

When X=1, the top ranked person is a female.

When X=2, the first person is a male and the second ranked person is a female.

Similarly, when X=3, the first two ranked persons are male and the third one is a female.

When X=4, the first three persons are male and the fourth one is a female.

When X=5, the first four persons are males and the fifth person is a female.

When X=6, the first five people are males and the sixth person is a female. The rest of the four people are also females since there are only five men in a sample space.

The probability for X=7, 8, 9, 10 is zero because there are only five men who can achieve the first five positions and the last highest rank that can be achieved by a woman is 6.

To compute the probabilities, we will use the formula:

<u>No. of ways a female can be ranked X/Total number of ways to rank 10 people</u>

Note that the total number of ways of ranking 10 different people is 10P10 or 10!

For X=1, the first position can be taken by any of the 5 women. The possible ways of the first person being a woman is 5C1. The rest of the 9 people can take any of the ranks. They can be ordered in 9P9 ways.

So, P(X=1) = (5C1)(9P9)/(10P10) = (5 x 362880)/(3628800) = 1/2

For X=2, the first rank must be taken by a male. The number of ways to arrange the first person as a male out of the 5 men can be calculated by 5P1. The second position must be taken by a female and rest of the 8 positions can be taken by any of the 8 people in 8P8 ways.

So, P(X=2) = (5P1)(5C1)(8P8)/(10P10) = (5 x 5 x 40320)/(3628800) = 5/18

For X=3, first two people must be men and the number of ways to arrange 2 out of 5 males at the first two positions is 5P2. The third position is a female. The rest of the 7 people can be ordered in 7P7 ways.

P(X=3) = (5P2)(5C1)(7P7)/(10P10) = (20 x 5 x 5040)/(3628800) = 5/36

P(X=4) = (5P3)(5C1)(6P6)/(10P10) = (60 x 5 x 720)/(3628800) = 5/84

P(X=5) = (5P4)(5C1)(5P5)/(10P10) = (120 x 5 x 120)/(3628800) = 5/252

P(X=6) = (5P5)(5C1)(4P4)/(10P10) = (120 x 5 x 24)/(3628800) = 1/252

P(X=7) = 0

P(X=8) = 0

P(X=9) = 0

P(X=10) = 0

7 0
3 years ago
In the game of Pick-A-Ball, there are 10 colored balls: 2 red, 4 white, and 4 blue. The balls have been placed into a small buck
MaRussiya [10]

Answer:

The probability of selecting the color of ball that you just selected(a red ball) is P(r) =  \frac{2}{10}

Step-by-step explanation:

From the question we are told that

  The total number of colored balls  is  n  =  10

   The number of red balls is r =  2 red

    The number of white ball is  w =  4

    The number of blue balls is  b  =  4

   The number of balls to be selected is  N  =  2 balls

    The cost of playing picking a ball is  c  =  $10

    The winnings is k =  \$ P(A)

Here P(A) is the probability of obtaining the exact sequence of result  and from the question it  is  P(A) =  0.10

Generally my price according to the question is  

     k =  \frac{0.10 }{10}

=>   k =  0.01

Let assume we selected a red ball

 Generally the probability of selecting a red ball is  mathematically represented as

       P(r) =  \frac{2}{10}

8 0
3 years ago
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