Part A;
There are many system of inequalities that can be created such that only contain points C and F in the overlapping shaded regions.
Any system of inequalities which is satisfied by (2, 2) and (3, 4) but is not stisfied by <span>(-3, -4), (-4, 3), (1, -2) and (5, -4) can serve.
An example of such system of equation is
x > 0
y > 0
The system of equation above represent all the points in the first quadrant of the coordinate system.
The area above the x-axis and to the right of the y-axis is shaded.
Part 2:
It can be verified that points C and F are solutions to the system of inequalities above by substituting the coordinates of points C and F into the system of equations and see whether they are true.
Substituting C(2, 2) into the system we have:
2 > 0
2 > 0
as can be seen the two inequalities above are true, hence point C is a solution to the set of inequalities.
Part C:
Given that </span><span>Natalie
can only attend a school in her designated zone and that Natalie's zone is
defined by y < −2x + 2.
To identify the schools that
Natalie is allowed to attend, we substitute the coordinates of the points A to F into the inequality defining Natalie's zone.
For point A(-3, -4): -4 < -2(-3) + 2; -4 < 6 + 2; -4 < 8 which is true
For point B(-4, 3): 3 < -2(-4) + 2; 3 < 8 + 2; 3 < 10 which is true
For point C(2, 2): 2 < -2(2) + 2; 2 < -4 + 2; 2 < -2 which is false
For point D(1, -2): -2 < -2(1) + 2; -2 < -2 + 2; -2 < 0 which is true
For point E(5, -4): -4 < -2(5) + 2; -4 < -10 + 2; -4 < -8 which is false
For point F(3, 4): 4 < -2(3) + 2; 4 < -6 + 2; 4 < -4 which is false
Therefore, the schools that Natalie is allowed to attend are the schools at point A, B and D.
</span>
Answer:
2 5/8 flour
1 1/2 teaspoon cinnamon
1/4 teaspoon salt
Step-by-step explanation:
Answer:
6π
Step-by-step explanation:
(135/360)×π×4²
(135/360)×π×16
=6π
Answer:
1. -10
2.x=8
3. x= 2
Step-by-step explanation:
1. x = 3, 2x+x+2x+5
=2(-3)+(-3)+2(-3)+5
= -6 +(-3)+(-6)+5
= -6 -3 -6 +5 Next you have to use BODMAS rule so first addition
= -6 -3 -1
= -9-1
= -10
2. 2(2x+1)+x=x+2x+18
=4x+2+x=3x+18 then collect like terms:
=4x+x+2=3x+18
=5x+2=3x+18
=5x+2-2=3x+18-2
=5x=3x+16
=5x-3x=3x-3x+16
= 2x=16
2x/2=16/2
x=8
3.2x+x+2x=10+x
=6x=10+x
=6x-x=10+x-x
=5x=10
=5x/5=10/5
x=2
If its helpful ❤❤❤
THANK YOU
