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Anarel [89]
3 years ago
8

Triangle XYZ is a right triangle.

Mathematics
1 answer:
Alecsey [184]3 years ago
3 0

Answer:

1.) 5

2.) 6

Step-by-step explanation:

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Area of circle
Gre4nikov [31]

Answer:

1. area

2. circle

3. equilateral

4. length

5. perimeter

6. polygon

7. regular polygon

8. trapezoid

9. legs

10. area of a circle

11. hexagon

12. octagon

13. inscribed polygon

14. apothem

15. composite figure

Step-by-step explanation:

4 0
3 years ago
Solve the equation c^2=4
mixas84 [53]

Answer:

c = 2 or c = -2

Step-by-step explanation:

c^2=4\\\\\sqrt{c^2}=\sqrt{4}\\\\ \boxed{c=2; c=-2}

Hope this helps.

7 0
3 years ago
Read 2 more answers
Jordan wants to make 1.25 using dollars half dollars and quarters how many different ways can she make 1.25
mihalych1998 [28]

Answer:

3

Step-by-step explanation:

1. 5 quarters.

2. 1 half dollar and 3 quarters.

3. 2 half dollars and a quarter.

7 0
3 years ago
Can some one help me please
Vinvika [58]

add all assets then add all liabilities

 if assets is higher she has a positive net worth of the difference

if liabilities is higher she has a negative net worth of the difference

3 0
3 years ago
Read 2 more answers
This year the CDC reported that 30% of adults received their flu shot. Of those adults who received their flu shot,
Vlad [161]

Using conditional probability, it is found that there is a 0.1165 = 11.65% probability that a person with the flu is a person who received a flu shot.

Conditional Probability

P(B|A) = \frac{P(A \cap B)}{P(A)}

In which

  • P(B|A) is the probability of event B happening, given that A happened.
  • P(A \cap B) is the probability of both A and B happening.
  • P(A) is the probability of A happening.

In this problem:

  • Event A: Person has the flu.
  • Event B: Person got the flu shot.

The percentages associated with getting the flu are:

  • 20% of 30%(got the shot).
  • 65% of 70%(did not get the shot).

Hence:

P(A) = 0.2(0.3) + 0.65(0.7) = 0.515

The probability of both having the flu and getting the shot is:

P(A \cap B) = 0.2(0.3) = 0.06

Hence, the conditional probability is:

P(B|A) = \frac{P(A \cap B)}{P(A)} = \frac{0.06}{0.515} = 0.1165

0.1165 = 11.65% probability that a person with the flu is a person who received a flu shot.

To learn more about conditional probability, you can take a look at brainly.com/question/14398287

7 0
2 years ago
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