Take the like terms on one side:
2m=6-14
2m = 8
m= 8/2
m= 4
Answer:
Douglas can race the go-karts at least 3 times.
Step-by-step explanation:
Given that:
Worth of game card = $20
Cost of go-kart = $3.50 each time
Amount Douglas wants to left = $7.75
Let,
x be the times Douglas can ride go-kart.
20 - 3.50x ≤ 7.75
-3.50x ≤ 7.75 - 20
-3.50x ≤ -12.25
3.50x ≤ 12.25
Dividing both sides by 3.50
Hence,
Douglas can race the go-karts at least 3 times.
Is it 3,-1,-4,6 because if you look at all your x values that should be your answer
Order the numbers from least to greatest. 15, 20, –13, –20, –9, 7 A. 20, 15, 7, –9, –13, –20 B. –20, –9, 15, 20, –13, 7 C. 7, –1
Dovator [93]
Answer:
D
Step-by-step explanation:
the numbers on answer D are in order on the number line from LEAST to GREATEST
Given that <span>Marjorie received successive discounts of 25%, 40% and 20% off the original price, on Black Friday.
</span><span>If
Marjorie wanted to purchase the same items this week, the single
percent discount she would have to receive off the original prices to
get the items for the same price that they were on Black Friday after
the three successive discounts is given by
1 - Single Discount = (1 - 0.25)(1 - 0.40)(1 - 0.20) = 0.75 x 0.60 x 0.80 = 0.36
Therefore, single discount = 1 - 0.36 = 0.64 = 64%.
</span>