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3 years ago

7

What are programs that are installed without the user knowing

Computers and Technology

1 answer:

Goshia [24]3 years ago

6 0

Hacks , aim bot wanna play fort nite some time I’m really good at it lol

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Write a c program to count the total number of commented characters and words in a c file taking both types of c file comments (

Tanzania [10]

#include<stdio.h>

#include<stdlib.h>

int comment1(FILE *fp)

{

char ch;

int count=0;

while(fscanf(fp,"%c",&ch)!=EOF)

{

if(ch=='\n')

{

return count;

}

count++;

}

return count;

}

int comment2(FILE *fp)

{

char ch;

int count=0;

while(fscanf(fp,"%c",&ch)!=EOF)

{

if(ch=='*')

{

fscanf(fp,"%c",&ch);

if(ch=='/')

{

return count;

}

count++;

}

count++;

}

return 0;

}

int main()

{

printf("Enter the file name:");

char s[1000],ch,ch1;

scanf("%s",s);

FILE*fp;

fp = fopen(s,"r");

int count=0;

while(fscanf(fp,"%c",&ch)!=EOF)

{

if(ch=='\"')

{

while(fscanf(fp,"%c",&ch)!=EOF)

{

if(ch=='\"')

{

break;

}

if(ch=='\\')

{

fscanf(fp,"%c",&ch);

}

}

}

else if(ch=='/')

{

fscanf(fp,"%c",&ch);

if(ch=='/')

{

count += comment1(fp);

}

else if(ch=='*')

{

count += comment2(fp);

}

}

}

printf("%d\n",count);

return 0;

}

3 0

3 years ago

Read 2 more answers

It takes 2 seconds to read or write one block from/to disk and it also takes 1 second of CPU time to merge one block of records.

Alexxx [7]

Answer:

Part a: For optimal 4-way merging, initiate with one dummy run of size 0 and merge this with the 3 smallest runs. Than merge the result to the remaining 3 runs to get a merged run of length 6000 records.

Part b: The optimal 4-way merging takes about 249 seconds.

Explanation:

The complete question is missing while searching for the question online, a similar question is found which is solved as below:

Part a

<em>For optimal 4-way merging, we need one dummy run with size 0.</em>

Merge 4 runs with size 0, 500, 800, and 1000 to produce a run with a run length of 2300. The new run length is calculated as follows $L_{mrg}=L_0+L_1+L_2+L_3=0+500+800+1000=2300$
Merge the run as made in step 1 with the remaining 3 runs bearing length 1000, 1200, 1500. The merged run length is 6000 and is calculated as follows

$L_{merged}=L_{mrg}+L_4+L_5+L_6=2300+1000+1200+1500=6000$

<em>The resulting run has length 6000 records</em>.

Part b

<u><em>For step 1</em></u>

Input Output Time

Input Output Time is given as

$T_{I.O}=\frac{L_{run}}{Size_{block}} \times Time_{I/O \, per\, block}$

Here

L_run is 2300 for step 01
Size_block is 100 as given
Time_{I/O per block} is 2 sec

So

$T_{I.O}=\frac{L_{run}}{Size_{block}} \times Time_{I/O \, per\, block}\\T_{I.O}=\frac{2300}{100} \times 2 sec\\T_{I.O}=46 sec$

So the input/output time is 46 seconds for step 01.

CPU Time

CPU Time is given as

$T_{CPU}=\frac{L_{run}}{Size_{block}} \times Time_{CPU \, per\, block}$

Here

L_run is 2300 for step 01
Size_block is 100 as given
Time_{CPU per block} is 1 sec

So

$T_{CPU}=\frac{L_{run}}{Size_{block}} \times Time_{CPU \, per\, block}\\T_{CPU}=\frac{2300}{100} \times 1 sec\\T_{CPU}=23 sec$

So the CPU time is 23 seconds for step 01.

Total time in step 01

$T_{step-01}=T_{I.O}+T_{CPU}\\T_{step-01}=46+23\\T_{step-01}=69 sec\\$

Total time in step 01 is 69 seconds.

<u><em>For step 2</em></u>

Input Output Time

Input Output Time is given as

$T_{I.O}=\frac{L_{run}}{Size_{block}} \times Time_{I/O \, per\, block}$

Here

L_run is 6000 for step 02
Size_block is 100 as given
Time_{I/O per block} is 2 sec

So

$T_{I.O}=\frac{L_{run}}{Size_{block}} \times Time_{I/O \, per\, block}\\T_{I.O}=\frac{6000}{100} \times 2 sec\\T_{I.O}=120 sec$

So the input/output time is 120 seconds for step 02.

CPU Time

CPU Time is given as

$T_{CPU}=\frac{L_{run}}{Size_{block}} \times Time_{CPU \, per\, block}$

Here

L_run is 6000 for step 02
Size_block is 100 as given
Time_{CPU per block} is 1 sec

So

$T_{CPU}=\frac{L_{run}}{Size_{block}} \times Time_{CPU \, per\, block}\\T_{CPU}=\frac{6000}{100} \times 1 sec\\T_{CPU}=60 sec$

So the CPU time is 60 seconds for step 02.

Total time in step 02

$T_{step-02}=T_{I.O}+T_{CPU}\\T_{step-02}=120+60\\T_{step-02}=180 sec\\$

Total time in step 02 is 180 seconds

Merging Time (Total)

<em>Now the total time for merging is given as </em>

$T_{merge}=T_{step-01}+T_{step-02}\\T_{merge}=69+180\\T_{merge}=249 sec\\$

Total time in merging is 249 seconds seconds

5 0

3 years ago

What is the name of the programming language created by Spu7Nix?

VMariaS [17]

The name of the programming language is “Brainfugd”

3 0

3 years ago

Read 2 more answers

There is a feature that allows you to lock the document, to avoid others making changes. True or False

Burka [1]

Answer:

yes there is

Explanation:

6 0

3 years ago

Name 3 examples of operating system software that are not Windows based.

anyanavicka [17]

Ubuntu, Linux, and Mint

4 0

3 years ago