Question

A painting is made from three different colors whose ratios are as follows: 4 parts blue, 3 parts red, and 3 parts green. The blue part of the painting took 12 gallons of paint. How many gallons of paint were needed for the green part of the painting

Answer 1

Answer: 9 gallons

Step-by-step explanation:

Given: Ratio of colors in painting:

4 parts blue, 3 parts red, and 3 parts green.

Total parts = 4+3+3 =10

Fraction of blue = $\dfrac{\text{Number of parts of blue}}{\text{total parts}}=\dfrac{4}{10}$

Since, Quantity of blue color used = 12 gallons

Let total quantity of color be x,

$\dfrac{4}{10}x=12\\\\\Rightarrow\ x=\dfrac{120}{4}=30\text{ gallons}$

Total color used = 30 gallons

Color used for green part only = $\dfrac{3}{10}\times30 = \text{9 gallons}$

Hence, 9 gallons of paint were needed for the green part of the painting.