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Genrish500 [490]
3 years ago
13

There are two friends. Each friend has a dollar to buy some pie. The first friend buys two-eighths of a pie for a dollar. The se

cond friend buys one-fourth of a pie for a dollar. Who receives the better deal?
Mathematics
1 answer:
Firlakuza [10]3 years ago
7 0

Answer:

Neither they get the same amount

Step-by-step explanation:

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A rectangular picture measuring 5 in. by 9 in. is surrounded by a frame with uniform width x. Write a quadratic function in stan
disa [49]
A=(5+2x)(9+2x)

A=45+10x+18x+4x^2

A=4x^2+28x+45

6 0
3 years ago
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Whats number two if someone can help thanks
OLEGan [10]
It would be c becuase 45/3=15
4 0
3 years ago
mayelle earns $18000 a year. After a raise, she earns $19500. Find the percent change and if it’s a decrease or increase
Aneli [31]
Ok, it's all pretty much like the "$50 coat is on sale for $35". 

<span>If the regular price of the coat is $50 and now it is on sale for $35, then it will cost you $15 less, like this: </span>
<span>$50 - $35 = $15 </span>

<span>You could also say the coat was discounted by $15, or the coat was reduced by $15, or you'll save $15 if you buy that coat ($50 - $15 = 35). </span>

<span>You could also put it in terms of percentages. If the discount is $15, you can figure that $15 is what percent of the regular price, like this: </span>
<span>$15 = X% of $50 </span>
<span>$15 = X% x $50 (divide both sides by 50 to isolate X) </span>
<span>15/50 = X% </span>
<span>.30 = X% (multiply by 100 to convert to a non-decimal) </span>
<span>30% = X </span>

<span>So, you can say all of the following and they all mean the same thing: </span>
<span>1. the $50 coat is on sale for $35 </span>
<span>2. the $50 coat is discounted by $15 </span>
<span>3. the $50 coat is reduced by $15 </span>
<span>4. you'll save $15 if you buy this coat </span>
<span>5. the $50 coat is on sale for 30% off </span>
<span>6. the $50 coat is discounted by 30% </span>
<span>7. you'll save 30% if you buy this coat </span>
<span>8. 30% savings! </span>
<span>9. Save 30%! </span>

<span>So, how does that apply to the $18,000 a year? Ok, if Shelby earns $18,000 this year and then earns $19,500 next year, then she gets an additional $1,500 ($19,500 - $18,000 = $1,500). In the coat problem, everything was discounted, on sale, going down. In this problem, everything is going up, increasing. </span>

<span>You know the dollar increase is $1,500. To figure the percent increase, you need to figure out that $1,500 is what % of $18,000. Remember, it's not the $19,500 that was increased; it was an increase on the $18,000: </span>
<span>$1,500 = X% of $18,000 </span>
<span>1,500/18,000 = X% </span>
<span>.083333 = X% </span>
<span>8.3333% = X </span>

<span>One more: If Shelby get a 10% increase in her salary at the end of one year, that's the same as saying that Shelby gets her salary plus she gets 10% more, like this: </span>

<span>$18,000 + (10% of $18,000) = </span>
<span>$18,000 + $1,800 = </span>
<span>$19,800 end of first year </span>

<span>For the second year, her salary begins at $19,800 and increases 10%, like this: </span>
<span>$19,800 + (10% x $19,800) = </span>
<span>$19,800 + $1,980 = </span>
<span>$21,780 end of second year </span>

<span>You can do it from here.</span>
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Answer: They sold 68 tickets at the door
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Check the picture below.

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\bf \textit{hyperbolas, vertical traverse axis }&#10;\\\\&#10;\cfrac{(y- k)^2}{ a^2}-\cfrac{(x- h)^2}{ b^2}=1&#10;\qquad &#10;\begin{cases}&#10;center\ ( h, k)\\&#10;vertices\ ( h,  k\pm a)\\&#10;c=\textit{distance from}\\&#10;\qquad \textit{center to foci}\\&#10;\qquad \sqrt{ a ^2 + b ^2}\\&#10;asymptotes\quad  y= k\pm \cfrac{a}{b}(x- h)&#10;\end{cases}\\\\&#10;-------------------------------

\bf \begin{cases}&#10;h=2\\&#10;k=-3\\&#10;a=6\\&#10;c=2\sqrt{10}&#10;\end{cases}\implies \cfrac{[y- (-3)]^2}{ 6^2}-\cfrac{(x- 2)^2}{ b^2}=1&#10;\\\\\\&#10;\cfrac{(y+3)^2}{ 36}-\cfrac{(x- 2)^2}{ b^2}=1&#10;\\\\\\&#10;c^2=a^2+b^2\implies (2\sqrt{10})^2=6^2+b^2\implies 2^2(\sqrt{10})^2=36+b^2&#10;\\\\\\&#10;4(10)=36+b^2\implies 40=36+b^2\implies 4=b^2&#10;\\\\\\&#10;\sqrt{4}=b\implies 2=b\\\\&#10;-------------------------------\\\\&#10;\cfrac{(y+3)^2}{ 36}-\cfrac{(x- 2)^2}{ 2^2}=1\implies \cfrac{(y+3)^2}{ 36}-\cfrac{(x- 2)^2}{ 4}=1

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2 years ago
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