Answer:
The vertex is at (-2,-8)
Step-by-step explanation:
You go left 2, and down 8, and then it's a scale of 1
The best in quality will probably be the 1470 but easiest to get i to is probably 1190 because if your sat score is way above their average they will think you are flaunting and deny your request
Plz mark as brainliest!
Answer:
C.0
since it's literally impossible for a triangle to have a right angle only squares and other shapes. triangles are made of acute angles
As you can see in this diagram, the answer is A, the ten-thousands place.
(a) Yes all six trig functions exist for this point in quadrant III. The only time you'll run into problems is when either x = 0 or y = 0, due to division by zero errors. For instance, if x = 0, then tan(t) = sin(t)/cos(t) will have cos(t) = 0, as x = cos(t). you cannot have zero in the denominator. Since neither coordinate is zero, we don't have such problems.
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(b) The following functions are positive in quadrant III:
tangent, cotangent
The following functions are negative in quadrant III
cosine, sine, secant, cosecant
A short explanation is that x = cos(t) and y = sin(t). The x and y coordinates are negative in quadrant III, so both sine and cosine are negative. Their reciprocal functions secant and cosecant are negative here as well. Combining sine and cosine to get tan = sin/cos, we see that the negatives cancel which is why tangent is positive here. Cotangent is also positive for similar reasons.
