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3 years ago

4 drinks for $3 is a unit rate?

Mathematics

1 answer:

yanalaym [24]3 years ago

7 0

Answer:

No, a unit rate is a rate for one quanity such as 1 drink for 0.75 cents.

Step-by-step explanation:

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-k+3k combine like terms to create an equivalent expression

Nimfa-mama [501]

Answer:

Step-by-step explanation:

3k and -k are both like terms, so you can combine them. Adding opposite signs works in the same way as subtraction, so you can rewrite the expression as 3k-k, which is 2k.

8 0

3 years ago

F(1) = 1 f(2) = 2 f(n) = f(n − 2) + f(n − 1) f(3)

sweet [91]

Answer:

f(3) = 3

Step-by-step explanation:

f(1) = 1

f(2) = 2

f(n) = f(n − 2) + f(n − 1)

f(3) = f(3 - 2) + f(3 - 1)

= f(1) + f(2) = 1 + 2 = 3

Special Note: Have you heard of the Fibonacci sequence?

The formula f(n) = f(n − 2) + f(n − 1) is used to find the terms of the of the Fibonacci sequence

8 0

3 years ago

Consider −75/3. Which TWO statements are correct?

kiruha [24]

B.) the quotient is -25

3 0

3 years ago

Read 2 more answers

PLEASE HELP ME THANKS ASAP

lara [203]

A = 28.26 units^2

Step-by-step explanation:

The formula for the area of a circle is:

$A=\pi r^2$

We can just plug in the numbers and solve.

$A=3.14*3*3$

$A=$

28.26 units^2

4 0

3 years ago

6. If the net investment function is given by

Pachacha [2.7K]

The capital formation of the investment function over a given period is the

accumulated capital for the period.

(a) The capital formation from the end of the second year to the end of the fifth year is approximately 298.87.

(b) The number of years before the capital stock exceeds $100,000 is approximately 46.15 years.

Reasons:

(a) The given investment function is presented as follows;

$I(t) = 100 \cdot e^{0.1 \cdot t}$

(a) The capital formation is given as follows;

$\displaystyle Capital = \int\limits {100 \cdot e^{0.1 \cdot t}} \, dt =1000 \cdot e^{0.1 \cdot t}} + C$

From the end of the second year to the end of the fifth year, we have;

The end of the second year can be taken as the beginning of the third year.

Therefore, for the three years; Year 3, year 4, and year 5, we have;

$\displaystyle Capital = \int\limits^5_3 {100 \cdot e^{0.1 \cdot t}} \, dt \approx 298.87$

The capital formation from the end of the second year to the end of the fifth year, C ≈ 298.87

(b) When the capital stock exceeds $100,000, we have;

$\displaystyle \mathbf{\left[1000 \cdot e^{0.1 \cdot t}} + C \right]^t_0} = 100,000$

Which gives;

$\displaystyle 1000 \cdot e^{0.1 \cdot t}} - 1000 = 100,000$

$\displaystyle \mathbf{1000 \cdot e^{0.1 \cdot t}}} = 100,000 + 1000 = 101,000$

$\displaystyle e^{0.1 \cdot t}} = 101$

$\displaystyle t = \frac{ln(101)}{0.1} \approx 46.15$

The number of years before the capital stock exceeds $100,000 ≈ 46.15 years.

Learn more investment function here:

brainly.com/question/25300925

6 0

2 years ago

4 drinks for $3 is a unit rate?​

4 drinks for $3 is a unit rate?