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Westkost [7]
3 years ago
5

A military jet flying with the wind travelled 1500 km in 1.5 hrs, but when the plane turned around, it took 1.875 hours to retur

n to its base. Find the rate of the plane in calm air and the rate of the wind. pls solve with 2 variables!
Mathematics
1 answer:
juin [17]3 years ago
5 0

Answer:

With wind = 1000 km /hr

In calm air = 800 km/hr

Step-by-step explanation:

With wind :

Distance traveled = 1500 km

Time taken = 1.5 hours

Speed of plane in air :

Speed = distance / time

Speed = 1500 km / 1.5 hours

Speed = 100 km pe hour

In calm air :

Time taken = 1.875 hours

Distance = 1500 km

Speed of wind in calm air :

Distance / time

1500 km / 1.875

= 800 km/hr

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(-8, -2) and (1, 9) find the slope
sergejj [24]

Answer:

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HELP PLEASE
Paraphin [41]

Answer:

x^4- x^3- 4x^2-3

Step-by-step explanation:

Given

f(x)= x^4- x^2+9

And

g(x)= x^(3 )+ 3x^2+12

We have to find

(f-g)(x)= ?

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We have to subtract the functions to find the above mentioned operation.

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(f-g)(x)=[x^4- x^2+9]-[x^(3 )+ 3x^2+12]

The minus will change the signs of function g.

= x^4- x^2+9- x^(3 )- 3x^2-12

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3 0
3 years ago
Evaluate help please!
UNO [17]
<h2><u>ABSOLUTE VALUE</u></h2>

The absolute value of a number is the distance from 0 to that number. The distance is positive, hence, the absolute value is always a positive number.

<h3>Exercise</h3>

Replace the value of x:

| x - 8 |

| -4 - 8 |

| -12 | = \large{\boxed{12}}

The absolute value of a number is the numerical value of the number, without regard to its sign.

<h3><u>Answer.</u> 12</h3>
3 0
3 years ago
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