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3 years ago

Sm1 please help me w this question!!!

Mathematics

1 answer:

Lady_Fox [76]3 years ago

6 0

Answer:

The answer is A, (1,2).

Step-by-step explanation:

Hope this helps!

8x-4(x+1) = 0

x =1

y = 1 + 1

y = 2

(x,y) = (1,2)

2 = 1 + 1

8 x 1 - 4 x 2 = 0

Simplify

2 = 2

0 = 0

Solution = (1 , 2)

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Which of the following is an improper integral:

Alla [95]

Answer:

∫₀² ln(x²) dx

Step-by-step explanation:

An integral is an improper integral if one or both endpoints is infinity, if the function is undefined at one or both endpoints, or if the function is discontinuous between the endpoints.

ln(x²) is undefined at x = 0.

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4 years ago

Trapezoid ABCD is congruent to trapezoid A"B"C"D". Which sequence of transformations could have been used to transform trapezoid

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Answer:ygggydtdgdgdfddgfs

Step-by-step explanation:

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3 years ago

Find the solution of the system of equations.

avanturin [10]

Answer:

Step-by-step explanation:

The number is 3.

Step-by-step explanation:

Finding the Number

To find the number, we have to translate the problem above to an algebraic equation. The algebraic equation refers to the statement of the equality of two algebraic expressions.

Equation:

Let "x" be the number.

4 is divided by a number - 4/x

3 divided by the number decreased by 2 - 3/x-2

"4 is divided by a number is equal to 3 divided by the number decreased by 2"

4/x = 3/x-2

Solution:

Cross multiply.

4/x = 3/x-2

x(3) = 4(x-2)

3x = 4x - 8

(Combine similar terms.)

3x - 4x = - 8

- x = - 8

- x/- 1 = - 8/- 1

x = 8

Final Answer:

Checking:

4/x = 3/x-2

4/8 = 3/8-2

1/2 = 3/6

1/2 = 1/2 ✔

7 0

3 years ago

What is the solution to this system?

Elza [17]

Answer:

Equation Form: x=−2,y=−2

Step-by-step explanation:

Eliminate the equal sides of each equation and combine.

3/2x+1=−x−4

Solve 3/2x+1=−x−4

for x. x=−2

Evaluate y when x=−2.

y=−2

The solution to the system is the complete set of ordered pairs that are valid solutions.

(−2,−2)

The result can be shown in multiple forms.

Point Form:

(−2,−2)

Equation Form:

x=−2,y=−2

7 0

3 years ago

The angle of elevation from me to the top of a hill is 51 degrees. The angle of elevation from me to the top of a tree is 57 deg

julia-pushkina [17]

Answer:

Approximately $101\; \rm ft$ (assuming that the height of the base of the hill is the same as that of the observer.)

Step-by-step explanation:

Refer to the diagram attached.

Let $\rm O$ denote the observer.
Let $\rm A$ denote the top of the tree.
Let $\rm R$ denote the base of the tree.
Let $\rm B$ denote the point where line $\rm AR$ (a vertical line) and the horizontal line going through $\rm O$ meets. $\angle \rm B\hat{A}R = 90^\circ$ .

Angles:

Angle of elevation of the base of the tree as it appears to the observer: $\angle \rm B\hat{O}R = 51^\circ$ .
Angle of elevation of the top of the tree as it appears to the observer: $\angle \rm B\hat{O}A = 57^\circ$ .

Let the length of segment $\rm BR$ (vertical distance between the base of the tree and the base of the hill) be $x\; \rm ft$ .

The question is asking for the length of segment $\rm AB$ . Notice that the length of this segment is $\mathrm{AB} = (x + 20)\; \rm ft$ .

The length of segment $\rm OB$ could be represented in two ways:

In right triangle $\rm \triangle OBR$ as the side adjacent to $\angle \rm B\hat{O}R = 51^\circ$ .
In right triangle $\rm \triangle OBA$ as the side adjacent to $\angle \rm B\hat{O}A = 57^\circ$ .

For example, in right triangle $\rm \triangle OBR$ , the length of the side opposite to $\angle \rm B\hat{O}R = 51^\circ$ is segment $\rm BR$ . The length of that segment is $x\; \rm ft$ .

$\begin{aligned}\tan{\left(\angle\mathrm{B\hat{O}R}\right)} = \frac{\,\rm {BR}\,}{\,\rm {OB}\,} \; \genfrac{}{}{0em}{}{\leftarrow \text{opposite}}{\leftarrow \text{adjacent}}\end{aligned}$ .

Rearrange to find an expression for the length of $\rm OB$ (in $\rm ft$ ) in terms of $x$ :

$\begin{aligned}\mathrm{OB} &= \frac{\mathrm{BR}}{\tan{\left(\angle\mathrm{B\hat{O}R}\right)}} \\ &= \frac{x}{\tan\left(51^\circ\right)}\approx 0.810\, x\end{aligned}$ .

Similarly, in right triangle $\rm \triangle OBA$ :

$\begin{aligned}\mathrm{OB} &= \frac{\mathrm{AB}}{\tan{\left(\angle\mathrm{B\hat{O}A}\right)}} \\ &= \frac{x + 20}{\tan\left(57^\circ\right)}\approx 0.649\, (x + 20)\end{aligned}$ .

Equate the right-hand side of these two equations:

$0.810\, x \approx 0.649\, (x + 20)$ .

Solve for $x$ :

$x \approx 81\; \rm ft$ .

Hence, the height of the top of this tree relative to the base of the hill would be $(x + 20)\; {\rm ft}\approx 101\; \rm ft$ .

6 0

3 years ago