<h2>Solving Quadratic Equations with the Quadratic Formula</h2>
<h3>Answer:</h3>
and 
<h3>Step-by-step Explanation: </h3>
Recall:
if we have a quadratic equation, 
, where 
, 
and 
are real numbers and 
, 
.
Given:
Solving for 
:
Solving with the positive value:
Solving with the negative value:
Answer:
y =3x-7
Step-by-step explanation:
y - 2 = 3(x-3)
y -2 = 3x -9
y = 3x-7
Answer:
Step by step explanation:
Not enough information to complete the problem. Please comment with the correct question so I can solve it.
The ordered pair is a solution of x - y = 2 and 3y - x = 8 is (x, y) = (7, 5)
<h3><u>Solution:</u></h3>
Given two equations are:
x - y = 2 and 3y - x = 8
<em><u>To find: orderes pair i.e (x, y)</u></em>
Let us consider:
x - y = 2 ------- eqn 1
3y - x = 8 --------- eqn 2
<em><u>Let us solve eqn 1 and eqn 2 to find values of "x" and "y"</u></em>
On rearranging eqn 2, we get
-x + 3y = 8 ------ eqn 3
Add eqn 1 and eqn 3
x - y = 2
-x + 3y = 8
(+) ---------------
0 + 2y = 10
2y = 10
<h3>y = 5</h3>
Therefore from eqn 1,
x - y = 2
x - 5 = 2
x = 5 + 2 = 7
<h3>x = 7</h3>
Thus the ordered pair to the given equations are (x, y) = (7, 5)
