How many puppies were rescued 12x+3=

We will assume that the trains pass by his house following a uniform distribution with values between 0 and 24. The probability of a train passing on a 9-hour time period is 9/24 = 3/8 = 0.375. Lets call Y the amount of trains passing by his house during that 9-hour period. Y follows a Binomail distribution with parameters 22 and 0.375.

P(Y ≤ 5) = P(Y = 0) + P(Y=1) + P(Y=2) + P(Y=3) + P(Y=4) + P(Y=5) =

${22 \choose 0} * 0.375^0*(1-0.375)^{22} + {22 \choose 1}*0.375^1*(1-0.375)^{21} +\\\\{22 \choose 2} * 0.375^2*(1-0.375)^{20} + {22 \choose 3}*0.375^3*(1-0.375)^{19} + \\{22 \choose 4} * 0.375^4*(1-0.375)^{18} + {22 \choose 5}*0.375^5*(1-0.375)^{17} = 0.11069$

I hope that works for you!

4 0

3 years ago

The vertices of shape K are at (4,7), (7, 7), (7,4) and (5, 5).

son4ous [18]

Answer:

To find the scale factor of the enlargement, compare the distance between a pair of corresponding points from both shapes.

<u>Shape K</u>

A = (4, 7)

B = (7, 7)

C = (7, 4)

D = (5, 5)

Horizontal distance between A (4, 7) and B (7, 7) = 3 units

<u>Shape L</u>

A' = (0, 11)

B' = (9, 11)

C' = (9, 2)

D' = (3, 5)

Horizontal distance between A' (0, 11) and B' (9, 11) = 9 units

9 ÷ 3 = 3

Therefore, Shape L is an enlargement of Shape K by scale factor 3.

To find the center of dilation (enlargement), draw two lines through 2 corresponding points (e.g. A and A', B and B') - the point of intersection of these lines is the center of dilation.

Therefore, the center of enlargement is (6, 5) (refer to the second attached image).

6 0

1 year ago

Joshua has $4,200 to invest for college. If Joshua invests $4,200 for 3 years and earns $630, what is the simple interest rate?

Rama09 [41]

Answer:

The simple interest rate is 5%.

This is possible with a rate of 6%, since in this case, his amount earned will be $5,208.

Step-by-step explanation:

This is a simple interest problem.

The simple interest formula is given by:

$E = P*I*t$

In which E is the amount of interest earned, P is the principal(the initial amount of money), I is the interest rate(yearly, as a decimal) and t is the time.

After t years, the total amount of money is:

$T = E + P$