yes because if you look you can see a pattern of 4 if we divide 2 AND 8 WE GET 4 AND SO.
a. Let
be a random variable representing the weight of a ball bearing selected at random. We're told that
, so

where
. This probability is approximately

b. Let
be a random variable representing the weight of the
-th ball that is selected, and let
be the mean of these 4 weights,

The sum of normally distributed random variables is a random variable that also follows a normal distribution,

so that

Then

c. Same as (b).
I believe the answer should be 4 and 2
Answer:
y = 4
Step-by-step explanation:
1) Simplify
to 243.

2) Simplify
to 531441.

3) Simplify
to 129140163.
4) Simplify
to 19683.

5) Simplify
to 6561.

6) Convert both sides to the same base.

7) Cancel the base of 9 on both sides.

Cheers,
ROR