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lana [24]
4 years ago
13

What is the common ratio of the following sequence? 80, 20, 5, ... A) -4 B) 1/4 C) 4

Mathematics
1 answer:
Stolb23 [73]4 years ago
6 0

\bf 80~~,~~20~~,~~5~\hfill \cfrac{20}{80}\implies \boxed{\cfrac{1}{4}}~~,~~ \cfrac{5}{20}\implies \boxed{\cfrac{1}{4}}~\hfill \stackrel{\textit{common ratio}}{\boxed{\cfrac{1}{4}}}

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Answer:

6 combinations

Step-by-step explanation:

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The point A, with coordinates (0,a,b) lies on the line l1, which has equation:
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a) The solution of the system is: (λ, a, b) = (- 5, - 11, - 26).

b) The coordinates of the point P are (x, y, z) = (- 16 / 3, - 43, 152 / 3).

c) Vectors <u>AP</u> and <u>PB</u> are <em>collinear</em> for their ends lie on the line. The ratio AP : PB is 83.248 : 73.491 (1.133 : 1).

<h3>How to analyze a line equation in vector form</h3>

a) In this problem we have a equation of the line in <em>vector</em> form, whose form is:

<u>r</u> = (5, 19, - 1) + λ · (1, 6, - 5)

Now we find the value of λ for the case <u>r</u> = (0, a, b):

(0, a, b) = (5, 19, - 1) + λ · (1, 6, - 5)

5 + λ = 0

19 + 6 · λ = a

- 1 + 5 · λ = b

The solution of the system is: (λ, a, b) = (- 5, - 11, - 26).

b) Then, the following condition must be fulfilled:

<u>OP</u> • <u>PB</u> = 0

(5 + λ, 19 + 6 · λ, - 1 + 5 · λ) • [(4, 13, 4) - (5 + λ, 19 + 6 · λ, - 1 - 5 · λ)] = 0

(5 + λ, 19 + 6 · λ, - 1 + 5 · λ) • (- 1 - λ, - 6 - 6 · λ, 5 + 5 · λ) = 0

(5 + λ) · (- 1 - λ) + (19 + 6 · λ) · (- 6 - 6 · λ) + (- 1 + 5 · λ) · (5 + 5 · λ) = 0

- (5 + λ) · (1 + λ) - 6 · (19 + 6 · λ) · (1 + λ) + 5 · (- 1 + 5 · λ) · (1 + λ) = 0

- (5 + 6 · λ + λ²) - 6 · (19 + 25 · λ + 6 · λ²) + 5 · (- 1 + 4 · λ + 5 · λ²) = 0

- 5 - 6 · λ - λ² - 114 - 150 · λ - 36 · λ² - 5 + 20 · λ + 25 · λ² = 0

- 12 · λ² - 136 · λ - 124 = 0

There are two solutions: λ₁ = - 1, λ₂ = - 31 / 3, whose points P are:

<u>r₁</u> = (5, 19, - 1) + (- 1) · (1, 6, - 5)

<u>r₁</u> = (4, 13, 4)

<u>r₂</u> = (5, 19, - 1) + (- 31 / 3) · (1, 6, - 5)

<u>r₂</u> = (- 16 / 3, - 43, 152 / 3)

Then, the coordinates of the point P are (x, y, z) = (- 16 / 3, - 43, 152 / 3).

c) Vectors <u>AP</u> and <u>PB</u> are <em>collinear</em> for their ends lie on the line. The ratio can be found by using the magnitudes of each vector:

Vector AP

<u>AP</u> = (- 16 / 3, - 43, 152 / 3) - (0, - 11, - 26)

<u>AP</u> = (- 16 / 3, - 32, 230 / 3)

AP = √(<u>AP</u> • <u>AP</u>)

AP ≈ 83.248

Vector PB

<u>PB</u> = (4, 13, 4) - (- 16 / 3, - 43, 152 / 3)

<u>PB</u> = (28 / 3, 56, - 140 / 3)

PB = √(<u>PB</u> • <u>PB</u>)

PB ≈ 73.491

The ratio AP : PB is 83.248 : 73.491 (1.133 : 1).

To learn more on lines: brainly.com/question/17188072

#SPJ1

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Amiraneli [1.4K]

Answer:

It is the last one 1 5/24


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3 years ago
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