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kodGreya [7K]
3 years ago
8

The length of a rectangular pool is 50 yards, and the width of the pool is 16 yards. What is the approximate length of the diago

nal of the pool
Mathematics
1 answer:
melisa1 [442]3 years ago
4 0

Answer:

52.5

Step-by-step explanation:

You would use the Pythagorean theorem to solve this. Using the formula,

a^2 + b^2 = ^2

You would have an equation of 50^2 + 16^2 = c ^2.

50^2 is 2500, and 16^2 is 256.

There, you have 2500+256 = c^2

add those together, and you have 2756.

Now, you have to find the square root of 2756 (to solve 2756 = c^2)

which leaves you with 52.4976189936 . Rounded to the nearest tenth, you end up with 52.5.

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Find the weekly wages for 43 hours of work at $11 per hour if the employee receives time and a half for all the hours over 40
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joshua,steve,antonioare baking pie.joshua has 1/2 cups of flour, steve has 1 3/4 cups of flour ,and Antonio has 1 4/6 cups of fl
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Answer:

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Step-by-step explanation:

I added 1/2 plus 1 3/4 plus 1 4/6 on a calculator and got 3.91666666667

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A well-known brokerage firm executive claimed that 50% of investors are currently confident of meeting their investment goals. A
VMariaS [17]

Answer:

p_v =P(Z  

If we compare the p value obtained and using the significance level given \alpha=0.005 we have p_v so we can conclude that we have enough evidence to reject the null hypothesis, and we can said that at 5% of significance the proportion of adults that said they are confident of meeting their goals  is significantly lower than 0.5 or 50% .  

Step-by-step explanation:

1) Data given and notation

n=200 represent the random sample taken

X represent the people that said they are confident of meeting their goals

\hat p=0.44 estimated proportion of adults that said they are confident of meeting their goals

p_o=0.5 is the value that we want to test

\alpha=0.005 represent the significance level

Confidence=99.5% or 0.995

z would represent the statistic (variable of interest)

p_v represent the p value (variable of interest)  

2) Concepts and formulas to use  

We need to conduct a hypothesis in order to test the claim that the proportion is less than 0.5.:  

Null hypothesis:p\geq 0.5  

Alternative hypothesis:p < 0.5  

When we conduct a proportion test we need to use the z statistic, and the is given by:  

z=\frac{\hat p -p_o}{\sqrt{\frac{p_o (1-p_o)}{n}}} (1)  

The One-Sample Proportion Test is used to assess whether a population proportion \hat p is significantly different from a hypothesized value p_o.

3) Calculate the statistic  

Since we have all the info requires we can replace in formula (1) like this:  

z=\frac{0.44 -0.5}{\sqrt{\frac{0.5(1-0.5)}{200}}}=-1.697  

4) Statistical decision  

It's important to refresh the p value method or p value approach . "This method is about determining "likely" or "unlikely" by determining the probability assuming the null hypothesis were true of observing a more extreme test statistic in the direction of the alternative hypothesis than the one observed". Or in other words is just a method to have an statistical decision to fail to reject or reject the null hypothesis.  

The significance level provided \alpha=0.005. The next step would be calculate the p value for this test.  

Since is left tailed test the p value would be:  

p_v =P(Z  

If we compare the p value obtained and using the significance level given \alpha=0.005 we have p_v so we can conclude that we have enough evidence to reject the null hypothesis, and we can said that at 5% of significance the proportion of adults that said they are confident of meeting their goals  is significantly lower than 0.5 or 50% .  

4 0
4 years ago
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