Distance from focus to vertex=distance from vertex to directix
from (6,2) to y=1, the distance is 1
the focus is 1/2 higher than the vertex
vertex=(6,1.5)
for
(x-h)^2=4p(y-k)
vertex=(h,k)
p=distance from vertex to directix
vertex=(6,1.5)
ditance=0.5
(x-6)^2=4(0.5)(y-1.5)
(x-6)^2=2(y-1.5) is the equation
or
y=0.5x^2-6x+19.5 or
y=0.5(x-6)^2+1.5
Hello there!
|a - b| - |c + d|
|-5 - 4| - |1 +(-3)|
=|-5 - 4| - |1 - 3|
= |-9| - |-2|
Solve for the absolute value
= 9 - 2
= 7
first you would multiply 25 x 3, which is 75 and then multiply 60 x 2 which is 120, then add 120 and 75 together, making the answer 195
Answer:
3
Step-by-step explanation:
therefore,
however, since logarithms cannot have negative arguments, x can only be +3
i.e. log(-3) is impossible, and will return MATH ERROR on a calculator.
