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Flura [38]
3 years ago
5

Christine has a rope that is 9 meters long. She cuts away a plece that is 3.29 meters long. How long is the remaining plece of r

ope?
Mathematics
2 answers:
natima [27]3 years ago
7 0

Answer:

9.00-3.29= 5.71 meters rope remaining

Sergeu [11.5K]3 years ago
4 0
5.71 rope remaining :) hope this helps
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A 165 inch pipe is cut into two pieces. One piece is four times the length of the other.Find the length of the shorter piece. Ho
coldgirl [10]

Answer:

Length of longer length=132 inches

Length of shorter length=33 inches

Step-by-step explanation:

Step 1: Determine total length of pipe

Total length of pipe=165 inches

Step 2: Derive expression for all the lengths

We can express all these lengths as follows;

L=l1+l2

where;

L=total length

l1=length of longer piece

l2=length of shorter piece

but;

length of longer piece=4×length of shorter piece

replacing;

l1=4l2

replacing;

L=165

l1=4×l2

165=l 2+4 l2

5 l2=165

l2=165/5

l2=33 inches

l1=length of longer length=33×4=132 inches

l2=length of shorter length=33 inches

4 0
3 years ago
Guys please help out with this asap ! thanks
yKpoI14uk [10]
You’re gonna wanna round up both sides of your equation which will give u 224, then divide both by 16 which will leave u with 178
7 0
2 years ago
What is the square root of 30
MArishka [77]
5.47722557505 :) have a nice day hope I helped
4 0
3 years ago
A travelling salesman sells milkshake mixing machines and on average sells 8.4 machines per month. He needs to sell at least 3 m
klio [65]

Answer:

P(X<3) = 0.01004

Step-by-step explanation:

From the given information:

Consider the application of Poisson distribution P(X = x ) = \dfrac{e^{-\lambda} \lambda ^x}{x!} with the parameter \lambda = 8.4;

Therefore, we can calculate the required probability as follows:

P(X< 3) = P(X = 0) + P(X = 1) + P(X =2)

P(X< 3) = \dfrac{e^{-8.4} 8.4^0}{0!} +  \dfrac{e^{-8.4} 8.4^1}{1!} +  \dfrac{e^{-8.4} 8.4^2}{2!}

P(X< 3) =e^{-8.4}( 1 + 8.4+35.28)

P(X<3) = 0.01004

6 0
3 years ago
Perform the indicated operations; reduce the answer to lowest terms. a. 3⁄10 + 6⁄10 b. 1⁄3 + 1⁄4 + 1⁄6 c. 5⁄6 – 3⁄6 d. 2⁄3 – 6⁄1
Setler [38]

Answer:

a. 3⁄10 + 6⁄10 = 9/10

b. 1⁄3 + 1⁄4 + 1⁄6 = 3/4

c. 5⁄6 – 3⁄6 = 1/3

d. 2⁄3 – 6⁄10 = 1/15

e. 4⁄10 × 3⁄7 = 6/35

f. 1⁄6 × 6⁄15 = 1/15

g. 1⁄8 ÷ 4⁄9 = 9/32

h. 1⁄5 ÷ 3⁄4 = 4/15

Step-by-step explanation:

a. 3⁄10 + 6⁄10

= 3*1 + 6*1 / 10

= 3+6/10

= 9/10

b. 1⁄3 + 1⁄4 + 1⁄6

since denominators are different we take LCM of 3,4,6 which is 12

= 1*4 + 1*3 + 1*2 / 12

= 4+3+2/12

= 9 ÷ 3 / 12 ÷ 3

= 3 / 4

c. 5⁄6 – 3⁄6

= 5 - 3 / 6

= 2 ÷ 2 / 6 ÷ 2 = 1/3

d. 2⁄3 – 6⁄10

LCM of 3 and 10 is 30

= 2 * 10 - 6 * 3 / 30

= 20 - 18 / 30

= 2 ÷ 2 / 30 ÷ 2 = 1/15

e. 4⁄10 × 3⁄7

= 12 ÷ 2 / 70 ÷ 2 = 6/35

f. 1⁄6 × 6⁄15

= 6 ÷ 6/90 ÷ 6 = 1/15

g. 1⁄8 ÷ 4⁄9

= 1/ 8 * 9/4

=9/32

h. 1⁄5 ÷ 3⁄4

=1/5 * 4/3

= 4/15

3 0
3 years ago
Read 2 more answers
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