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Aloiza [94]
3 years ago
10

I am doing a math project for Geometry. I am using Singapore Flyer as example for a circle. This is the information I know so fa

r: diameter = 150m (radius=75), Circumference = 471 m, Area = 17,662.50 m, there are 28 capsules/compartments where people go into ride it. I now need to get the measure of the center angle and the arc length. I am pretty sure I need to use formula 2(pi)(r)(x/360) to solve for x = central angle. If I input what I know (radius = 75) 2(3.14)(75)(x/360) = 471(x/360) = 471x/360 = x = 1.3083 repeating. Is this right or do I need to use a different formula? Thank you all for your help.
Mathematics
1 answer:
My name is Ann [436]3 years ago
8 0

Answer:

Yea its correct! good job yea there are not any mistakes

Step-by-step explanation:

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Step-by-step explanation:

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3 years ago
2.3×10⁹=(1×10³)(2.3×10^n)​
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Answer:

<em>n = 6 </em>

Step-by-step explanation:

2.3 × 10^{9} = (1 × 10³)(2.3 × 10^{n} )

(1 × 10³)(2.3 × 10^{n} ) = (1)(2.3) × (10³)( 10^{n} ) = 2.3 × 10^{3+n}

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2 years ago
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Step-by-step explanation:

5 0
2 years ago
Someone please help me thank you
german

Answer:

4

Step-by-step explanation:

7x = x² - 8

=> x² - 7x - 8 = 0

use quadratic formula:

a = 1, b = -7, c = -8

x = \frac{-(1)±\sqrt{(-7)^{2} - 4(1)(-8) } }{2(1)} <em>(pls ignore the "A" I don't know why it's showing up)</em>

=> x = \frac{-1±\sqrt{49 + 32} }{2}

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2 years ago
Read 2 more answers
Before the distribution of certain statistical software, every fourth compact disk (CD) is testedfor accuracy. The testing proce
pishuonlain [190]

Answer:

P(T∩E) = 0.017

Step-by-step explanation:

Since every fourth CD is tested. Thus if T is the event that represents 4 disks being tested,

P(T) = 1/4 = 0.25

Let Fi represent event of failure rate. So from the question,

P(F1) = 0.01 ; P(F2) = 0.03 ; P(F3) =0.02 ; P(F4) = 0.01

Also Let F'i represent event of success rate. And we have;

P(F'1) = 1 - 0.01 = 0.99 ; P(F'2) = 1 - 0.03 = 0.97; P(F'3) = 1 - 0.02 = 0.98; P(F'4) = 1 - 0.01 = 0.99

Since all programs run independently, the probability that all programs will run successfully is;

P(All programs to run successfully) =

P(F'1) x P(F'2) x P(F'3) x P(F'4) =

0.99 x 0.97 x 0.98 x 0.97 = 0.932

Now, that all 4 programs failed will be = 1 - 0.932 = 0.068

Let E be denote that the CD fails the test. Thus P(E) = 0.068

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8 0
3 years ago
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